3 years ago

Please help! Will give brainliest. 15 points

Mathematics

1 answer:

Leokris [45]3 years ago

6 0

Answer:

See Explanation

Step-by-step explanation:

$In\: \triangle ABD \: \&\: \triangle ACB\\\angle BAD \cong \angle CAB... (common \: \angle 's) \\\angle ABD \cong \angle ACB... (each\: 45\degree) \\\therefore \triangle ABD \: \sim\: \triangle ACB... (By\: AA\: postulate) \\$

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