Given f(x)=-3x+2 , fine the domain value if the range value is -10

My quadrilateral has no lines of symmetry but it does have rotation symmetry. what is it?”

Elina [12.6K]

We have to identify the quadrilateral with no line of symmetry and have rotational symmetry.

Line of symmetry is the imaginary line which divide the given quadrilateral in two equal halves.

Rotational symmetry is when an object is rotated around a center point (turned) a number of degrees and the object appear the same.

Parallelogram is a quadrilateral which has no line of symmetry as we can not draw any imaginary line which divides the parallelogram in two equal halves.

But Parallelogram has rotational symmetry as when a parallelogram is rotated around a center point (turned) a number of degrees and parallelogram appear the same.

Hence, Parallelogram is the quadrilateral.

8 0

4 years ago

Suppose that 3 balls are chosen without replacement from an urn consisting of 5 white and 8 red balls. Let Xi equal 1 if the ith

Katarina [22]

Answer:

The joint probability mass function table is provided below.

Step-by-step explanation:

The experiment consist of drawing 3 balls from an urn containing 5 white and 8 red balls.

The random variable Xi is defined as follows:

Xi = 1; if the ith ball is white

Xi = 0; otherwise.

Then X₁ = the 1st ball is white and X₂ = the 2nd ball is white.

The sample space is as follows:

S = {(X₁ = 0, X₂ = 0), (X₁ = 0, X₂ = 1), (X₁ = 1, X₂ = 0), (X₁ = 1, X₂ = 1)}

Compute the probability of each event in the sample space as follows:

$P(X_{1} = 0, X_{2}= 0)=\frac{8}{13} \times\frac{7}{12}=\frac{14}{39}$

$P(X_{1} = 0, X_{2}= 1)=\frac{8}{13} \times\frac{5}{12}=\frac{10}{39}$

$P(X_{1} = 1, X_{2}= 0)=\frac{5}{13} \times\frac{8}{12}=\frac{10}{39}$

$P(X_{1} = 1, X_{2}= 1)=\frac{5}{13} \times\frac{4}{12}=\frac{5}{39}$

The joint probability mass function table is provided below.

4 0

3 years ago

What is the equation in standard form of an ellipse centered at the origin and vertex (1,0) and focus (4,0)

Dmitriy789 [7]

The correct question is
What is the equation in standard form of an ellipse centered at the origin and vertex (4,0) and focus (1,0)


we know that
Standard form of equation for an ellipse with horizontal major axis is
(x-h)²/a²+(y-k)²/b²=1
the center is the origin
so
(h,k) is (0,0)length of horizontal major axis------> 8=2a-----> a=4
a²=16
c=1 (distance from center to focal point)
c²=1
b²=a²-c²-----> b²=16-1----> b²=15

the equation is
(x)²/16+(y)²/15=1

the answer is
(x)²/16+(y)²/15=1

3 0

3 years ago

Dilacey takes out a loan from the bank that charges a 10% interest rate. After 18 months,

ra1l [238]

Answer:

Dilacey took a loan of $2800

Step-by-step explanation:

P=(Simple Interest×100)/R×T

P=$420×100/10×1½

P=$42000/15

P=$2800

4 0

3 years ago

Let f(x)=x-3 and g(x)= x^2-x. Find and simplify the expression. (f+g)(2)

ValentinkaMS [17]

Answer:

Step-by-step explanation:

Given :

f(x) = x − 3

g(x) = x² − x

Note : (f+g)(x) = f(x) + g(x)

then

(f+g)(2) = f(2) + g(2)

= (2 - 3) + (2² - 2)

= -1 + 2

= 1

another method:

(f+g)(x) = f(x) + g(x) = x − 3 + x² − x = x² - 3

then

(f+g)(2) = 2² - 3 = 4 - 3 = 1

8 0

3 years ago