The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
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Answer:
The specific gravity of kerosene is 0.82
Step-by-step explanation:
Let
x -----> the weight in grams of a cubic centimeter of Kerosene
y ----> the weight in grams of a cubic centimeter of water
z ---> the specific gravity of a substance
so
we have
substitute the values
Answer:
Given f(x)=32
So we can substitute 32 in place of 'x'
So, f(x)=3x-1
= f(x)=3(32)-1
= f(x)=96-1
= f(x)=95
f(x)=3x-1 = 95
Answer:
15:25
Step-by-step explanation:
15 correct from 25 total
