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3 years ago

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Jessie has some nickels, dimes, and quarters in her bank. The number of coins is 26 . The expression 0.05⁢n+0.10⁢d+0.25⁢q repres

ents the value of the coins, which is $2.65 . Jessie has two more dimes than she does quarters. How many of each coin does Jessie have?

1 answer:

Westkost [7]3 years ago

7 0

Use the substituting equation to solve

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3 years ago

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$\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }$

<em><u>Solution:</u></em>

From given question,

Number of pounds Jake carry = $6\frac{1}{4} \text{ pounds }$

Number of pounds his father carry is $1\frac{5}{7}$ times as much as jake

To find: Number of pounds Jake father can carry

<em><u>Convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

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<em><u>Then according to question,</u></em>

$\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}$

$\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }$

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