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Darina [25.2K]
3 years ago
5

Jessie has some nickels, dimes, and quarters in her bank. The number of coins is 26 . The expression 0.05⁢n+0.10⁢d+0.25⁢q repres

ents the value of the coins, which is $2.65 . Jessie has two more dimes than she does quarters. How many of each coin does Jessie have?
Mathematics
1 answer:
Westkost [7]3 years ago
7 0
Use the substituting equation to solve
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3 years ago
Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.
ioda

\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

<em><u>Solution:</u></em>

From given question,

Number of pounds Jake carry = 6\frac{1}{4} \text{ pounds }

Number of pounds his father carry is 1\frac{5}{7} times as much as jake

To find: Number of pounds Jake father can carry

<em><u>Convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}

<em><u>Then according to question,</u></em>

\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}

\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

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3 years ago
Please help me with this homework
TiliK225 [7]

Answer:

what do you need help with

Step-by-step explanation:

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3 years ago
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