You find a point at the intersection of a plane and line.
Answer:
9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;
(x - 2)²/2² - (y + 3)²/3² = 1
Step-by-step explanation:
The standard form of a hyperbola is given as follows;
(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1
The given equation is presented as follows;
9·x² - 36·x = 4·y² + 24·y + 36
By completing the square, we get;
(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)
(3·x - 6)² - 36 = (2·y + 6)²
(3·x - 6)² - (2·y + 6)² = 36
(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1
(3·x - 6)²/6² - (2·y + 6)²/6² = 1
3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1
(x - 2)²/2² - (y + 3)²/3² = 1
The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.
The volume of the triangular prism is:
V = (1/2) * (b) * (h) * (H)
Where,
b: base of the triangle
h: triangle height
H: prism height
Substituting:
V = (1/2) * (9) * (12) * (19)
V = 1026 cm ^ 3
The volume of the cylinder is:
V = (pi) * (r ^ 2) * (h)
Where,
r: radio
h: height
Substituting:
V = (3.14) * ((14/2) ^ 2) * (11)
V = 1692.46 yd^3
