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Lesechka [4]
3 years ago
9

Evaluate the expression you got in part f for d = 5.

Mathematics
1 answer:
Triss [41]3 years ago
8 0

Answer:

Before you get started, take this readiness quiz.

Is n÷5 an expression or an equation? If you missed this problem, review Example 2.1.4.

Simplify 45. If you missed this problem, review Example 2.1.6.

Simplify 1+8•9. If you missed this problem, review Example 2.1.8.

Evaluate Algebraic Expressions

In the last section, we simplified expressions using the order of operations. In this section, we’ll evaluate expressions—again following the order of operations.

To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number. To evaluate an expression, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations.

Example 2.3.1: evaluate

Evaluate x+7 when

x=3

x=12

Solution

To evaluate, substitute 3 for x in the expression, and then simplify.

x+7

Substitute.

3+7

Add.

10

When x=3, the expression x+7 has a value of 10.

To evaluate, substitute 12 for x in the expression, and then simplify.

x+7

Substitute.

12+7

Add.

19

When x=12, the expression x+7 has a value of 19. Notice that we got different results for parts (a) and (b) even though we started with the same expression. This is because the values used for x were different. When we evaluate an expression, the value varies depending on the value used for the variable.

exercise 2.3.1

Evaluate: y+4 when

y=6

y=15

Answer a

Answer b

exercise 2.3.2

Evaluate: a−5 when

a=9

a=17

Answer a

Answer b

Example 2.3.2

Evaluate 9x−2, when

x=5

x=1

Solution

Remember ab means a times b, so 9x means 9 times x.

To evaluate the expression when x=5, we substitute 5 for x, and then simplify.

9x−2

Substitute 5 for x.

9⋅5−2

Multiply.

45−2

Subtract.

43

To evaluate the expression when x=1, we substitute 1 for x, and then simplify.

9x−2

Substitute 1 for x.

9⋅1−2

Multiply.

9−2

Subtract.

7

Notice that in part (a) that we wrote 9•5 and in part (b) we wrote 9(1). Both the dot and the parentheses tell us to multiply.

exercise 2.3.3

Evaluate: 8x−3, when

x=2

x=1

Answer a

Answer b

exercise 2.3.4

Evaluate: 4y−4, when

y=3

y=5

Answer a

Answer b

Example 2.3.3: evaluate

Evaluate x2 when x=10.

Solution

We substitute 10 for x, and then simplify the expression.

x2

Substitute 10 for x.

102

Use the definition of exponent.

Evaluate: 2x when x=6.

Answer

exercise 2.3.8

Evaluate: 3x when x=4.

Answer

Example 2.3.5: evaluate

Evaluate 3x+4y−6 when x=10 and y=2.

Solution

This expression contains two variables, so we must make two substitutions.

3x+4y−6

Substitute 10 for x and 2 for y.

3(10)+4(2)−6

Multiply.

30+8−6

Add and subtract left to right.

32

When x=10 and y=2, the expression 3x+4y−6 has a value of 32.

exercise 2.3.9

Evaluate: 2x+5y−4 when x=11 and y=3

Answer

exercise 2.3.10

Evaluate: 5x−2y−9 when x=7 and y=8

Answer

Example 2.3.6: evaluate

Evaluate 2x2+3x+8 when x=4.

Solution

We need to be careful when an expression has a variable with an exponent. In this expression, 2x2 means 2•x•x and is different from the expression (2x)2, which means 2x•2x.

2x2+3x+8

Substitute 4 for each x.

2(4)2+3(4)+8

Simplify 42.

2(16)+3(4)+8

Multiply.

32+12+8

Add.

52

exercise 2.3.11

Evaluate: 3x2+4x+1 when x=3.

Answer

exercise 2.3.12

Evaluate: 6x2−4x−7 when x=2.

Answer

Identify Terms, Coefficients, and Like Terms

Algebraic expressions are made up of terms. A term is a constant or the product of a constant and one or more variables. Some examples of terms are 7, y, 5x2, 9a, and 13xy.

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How do you solve for x is this triangle
asambeis [7]

Answer:

x = 3.46 units

Step-by-step explanation:

Given:

angle RQS = 60

QS = 2 units

PS = 8 units

To Find:

RS = x = ?

Solution:

In triangle QRS,

tan angle Q = RS / QS

tan 60 = x / 2

root 3 = x / 2

x = 2 root 3

x = 2 x 1.73

Therefore, x = 3.46 units

PLEASE MARK ME AS BRAINLIEST!!!

4 0
3 years ago
A CHICKEN COOP HOLDS A TOTAL OF 10 HENS OR 20 CHICKS. IF 2/5THS OF THE HENS IN A FULL COOP ARE REMOVED, HOW MANY NEW CHICKS COUL
LiRa [457]

Answer:

8 new chicks can be fitted in the coop.

Step-by-step explanation:

A chicken coop holds 10 hens or 20 chicks.

That means space in the coop for 10 hens = space for 20 chicks

Or space for 1 hen = space for 2 chicks

Now \frac{2}{5}th of the hens were removed from the coop.

So, number of hens removed from the coop = \frac{2}{5}\times 10

= 4 hens

And space for 4 hens in the coop = space for the 8 chicks

Therefore, 8 new chicks can be fitted in the coop.

5 0
3 years ago
I need some help on this, algebra, need some answers asap, please! Brainliest and 10 pts to the most helpful answer :)
tigry1 [53]
12 = r - (34 - 2)
subtract he 2 from 34

12 = r - (32)
add 32 to each side

r = 44

Check:

12 = 44 - (34 - 2)
12 = 44 - 32
12 = 12 :)
5 0
3 years ago
What is the algebraic expression for the quotient of z and 3
Zielflug [23.3K]
The quotient of z and 3.

quotient = ÷

z/3

The answer is A.
4 0
3 years ago
PLEASE HELP ME (40 POINTS)
CaHeK987 [17]

For each equation give X a value and solve for Y, do this at least two times for each equation.

Plot those dots on a graph to draw two lines.

The solution is where the two lines cross.

You will see the lines cross at (-1,-2)

7 0
3 years ago
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