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Ivan
3 years ago
15

At STP graphite and diamond are two solid forms of carbon which statement explains why these two forms of carbon differ in hardn

ess
Chemistry
2 answers:
zysi [14]3 years ago
5 0
It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer. At STP graphite and diamond are two solid forms of carbon, the statement that explains why these two forms of carbon differ in hardness is this: <span>Graphite and diamond have different molecular structures. Hope this helps.</span>
QveST [7]3 years ago
4 0

Answer:

graphite and diamond have different molecule structure

Explanation:

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If I add water to oil what will happen
Alex

The oil, even a little drop, will spread out over the water surface and break up into many little blobs.

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3 years ago
An element, X, can form a chloride (XCl3) and an iodide (XI3). The chloride can be converted quantitatively into the iodide when
Arlecino [84]

Answer : The chemical symbol for this element is, (La)

Explanation : Given,

Mass of XCl_3 = 0.760 g

Mass of XI_3 = 1.610 g

The given chemical reaction is:

2XCl_3+3I_2\rightarrow 2XI_3+3Cl_2

First we have to calculate the moles of XCl_3 and XI_3.

\text{Moles of }XCl_3=\frac{\text{Mass of }XCl_3}{\text{Molar mass of }XCl_3}

Molar mass of Cl = 35.5 g/mole

Let the molar mass of element 'X' be, M

\text{Moles of }XCl_3=\frac{0.760}{[M+3(35.5)]}

and,

\text{Moles of }XI_3=\frac{\text{Mass of }XI_3}{\text{Molar mass of }XI_3}

Molar mass of I = 126.9 g/mole

Let the molar mass of element 'X' be, M

\text{Moles of }XI_3=\frac{1.610}{[M+3(126.9)]}

From the balanced chemical reaction we conclude that,

The moles of ratio of XCl_3 and XI_3 is, 1 : 1

That means,

\frac{0.760}{[M+3(35.5)]}=\frac{1.610}{[M+3(126.9)]}

\frac{0.760}{[M+106.5]}=\frac{1.610}{[M+380.7]}

M=138.667g/mol

From this we conclude that the element (X) is lanthanum (La) that has molecular weight, 138.667 g/mol.

Hence, the chemical symbol for this element is, (La)

6 0
4 years ago
Which change to the experimental design would improve the reliability of the engineers' measurements?
luda_lava [24]

Answer:

c

Explanation:

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4 0
3 years ago
How many moles are present in 63.80L of oxygen gas, O2?
matrenka [14]

Answer:

2.85moles of oxygen gas

Explanation:

Given parameters:

Volume of oxygen gas  = 63.8L

Unknown:

Number of moles  = ?

Solution:

We assume that the gas is under standard temperature and pressure. To find the number of moles, use the expression below:

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 So;

       63.8L of oxygen gas will take up a volume of

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The organ system that moves air into, around, and out the body
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Its a Respiratory System, hope that helped your question :)
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