2 years ago

How many liters are in .0025 millililiters

Chemistry

1 answer:

jekas [21]2 years ago

8 0

Answer: 0.0000025 liters

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A sample of neon gas occupies 105 L at 27°C under a pressure of

Viefleur [7K]

Answer: Volume occupied by given neon sample at standard condition is 123.84 L.

Explanation:

Given: $V_{1}$ = 105 L, $T_{1} = 27^{o}C = (27 + 273) K = 300 K$ , $P_{1}$ = 985 torr

At standard conditions,

$T_{2}$ = 273 K, $P_{2}$ = 760 K, $V_{2}$ = ?

Formula used to calculate the volume is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{985 torr \times 105 L}{300 K} = \frac{760 torr \times V_{2}}{273 K}\\V_{2} = \frac{94116.75}{760} L\\= 123.84 L$

Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.

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2 years ago

2C6H10 + 17O2 = 12CO2 + 10H2O

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Answer:

n O2 = 2.125 mol

Explanation:

balanced reaction:

2C6H10 + 17O2 → 12CO2 + 10H2O

∴ n CO2 = 1.5 mol

⇒ n O2 = (1.5 mol CO2)*(17 mol O2/12 mol CO2)

⇒ n O2 = 2.125 mol

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