All categories

2 years ago

Solve for x. 10x + 44 8x - 23

Mathematics

2 answers:

meriva2 years ago

5 0

Answer:

Simplifying

10x + 44 = 8X + -23

Reorder the terms:

44 + 10x = 8X + -23

Reorder the terms:

44 + 10x = -23 + 8X

Solving

44 + 10x = -23 + 8X

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-44' to each side of the equation.

44 + -44 + 10x = -23 + -44 + 8X

Combine like terms: 44 + -44 = 0

0 + 10x = -23 + -44 + 8X

10x = -23 + -44 + 8X

Combine like terms: -23 + -44 = -67

10x = -67 + 8X

Divide each side by '10'.

x = -6.7 + 0.8X

Simplifying

x = -6.7 + 0.8XStep-by-step explanation:

koban [17]2 years ago

3 0

You need an answer to get x. like it needs to be

10x+44=100 or something in order to find x

You might be interested in

What time is 17 hours after 1:00 p.m?

lana66690 [7]

Answer:

6am

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve system by subsubstitution?<br> 14x-2y=46<br> -7x+y=-23

e-lub [12.9K]

$14x-2y=46 \\
-7x+y=-23 \\ \\
\hbox{solve the 2nd equation for y:} \\
-7x+y=-23 \\
y=7x-23 \\ \\
\hbox{substitute 7x-23 for y in the 1st equation:} \\
14x-2(7x-23)=46 \\
14x-14x+46=46 \\
14x-14x=46-46 \\
0=0 \\ \\
\boxed{\hbox{infinitely many solutions}}$

8 0

3 years ago

Stephanie's graduation picnic costs $7 for every attendee. Write an equation that shows the relationship between the attendees,

Serjik [45]

Are you studied on his work

4 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$