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3 years ago

Three consecutive odd integers whose sum is 366

Mathematics

1 answer:

iren2701 [21]3 years ago

8 0

n, n + 2, n + 4 - three consecutive odd integers

366 - the sum

Equation:

n + (n + 2) + (n + 4) = 366

n + n + 2 + n + 4 = 366

3n + 6 = 366 |subtract 6 from both sides

3n = 360 |divide both sides by 3

n = 120

n + 2 = 120 + 2 = 122

n + 4 = 120 + 4 = 124

Answer: 120, 122, 124.

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Part b)

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Hello,

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