Answer:
n=-6
Step-by-step explanation:
distribute -7 into (4n+8)
-10n+50=-28n-56-2
combine like terms
-10n+50=-28n-58
add -28n on both sides
-10n+28n+50=-58
combine like terms again
18n+50=-58
subtract 50 on both sides
18n=-108
divide both sides by 18
x=-6
hope this helps
$42,500 because 45900 dividede by 1.08 is 42500
JK = JH + HK
JK = 82
JH = 22
So, HK = 82 - 22 = 60, or choice (C).
If my ans was helpful u can follow me
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
