All categories

3 years ago

Can someone help me find the perimeter

Mathematics

2 answers:

zepelin [54]3 years ago

8 0

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 15

Explanation:

4 + 3 + 6 + 2 = 15

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Ymorist [56]3 years ago

7 0

The answer is 15 I believe

You might be interested in

The ratio of lollipops to pieces of bubble gum at the party is 2 to 3. There are 24 lollipops. What is the total number of lo

disa [49]

Answer: 40

Step-by-step explanation: first make the ratio into a fraction, 2/3

then make 24 into a fraction with the numerator as a variable and the denominator as 24, x/24

then cross multiply 2 and 24.

2x24=48

then divide 48 by 3, 16.

last add the number of lollipops to 16 and the answer is 40.

5 0

2 years ago

Read 2 more answers

I need help please 20 or more points please

Norma-Jean [14]

Answer: V, V, (-5, -5.5)

Step-by-step explanation:

7 0

2 years ago

Find the equation of the inverse.<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7B2%7D%5E%7Bx%20%2B%205%7D%20%20-%206" id="TexF

Contact [7]

Find the equation of the inverse.

$y = {2}^{x + 5} - 6$

we have

$y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6$

step 1

Exchange the variables

x for y and y for x

$x=\{2\}^{\{y+5\}}-6$

step 2

Isolate the variable y

$(x+6)=2^{(y+5)}$

apply log both sides

$\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\ \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}$

step 3

Let

$f^{(-1)}(x)=y$

therefore

the inverse function is

$f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5$

7 0

1 year ago

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot represents class first. From the first box plot, we get

$\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

Second box plot represents class second. From the second box plot, we get

$\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0

2 years ago

Here a subtraction problem that has been solved incorrectly what is the right way 74-25=59

jek_recluse [69]

Answer:

74-25 is 49

Step-by-step explanation:

7 0

2 years ago