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3 years ago

Can someone help me find the perimeter

Mathematics

2 answers:

zepelin [54]3 years ago

8 0

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Answer: 15

Explanation:

4 + 3 + 6 + 2 = 15

I hope this helped!

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- Zack Slocum

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Ymorist [56]3 years ago

7 0

The answer is 15 I believe

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Simplify 1 - 2u - 9 - (-5u)

RSB [31]

Answer:

$1 - 2u - 9 - ( - 5u) \\ = 1 - 9 - 2u - - 5u \\ = - 8 - 2u + 5u \\ = - 8 + 3u \\ thank \: you$

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3 years ago

Read 2 more answers

Consider the equation 6x +7=3x � 5. Which of the following possible first steps would prevent having to deal with fractions when

11Alexandr11 [23.1K]

Answer:

D. I or II only

Step-by-step explanation:

By a small online search, I've found that the equation is:

6x + 7 = 3x - 5

And the options are:

I. Combining the 6x and 3x terms

II. Combining the 7 and 5

III. Dividing both sides of the equation by 6

A. I only

B. II only

C. III only

D. I or II only

E. I or II or III

So, let's solve the equation in such a way that we can prevent the use of fractions:

6x + 7 = 3x - 5

We can use I and II, combining one in each side, so we get (so we use I and II at the same time)

6x - 3x = -5 - 7

solving these, we get:

(6 - 3)*x = -12

3*x = -12

and -12 is divisible by 3, so if we divide in both sides by 3, we get:

x = -12/3 = -4

x = -4

So we avoided working with fractions, and we used I and II.

Then the first step could be either I or II (the order does not matter)

Then the correct option is:

D. I or II only

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3 years ago

Allison ran 5 1/4 miles. jimmy ran 3 2/3 miles. how much father did allison run than jimmy

Llana [10]

let's firstly convert the mixed fractions to improper fractions, and then subtract.

$\bf \stackrel{mixed}{5\frac{1}{4}}\implies \cfrac{5\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{21}{4}}~\hfill \stackrel{mixed}{3\frac{2}{3}}\implies \cfrac{3\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{11}{3}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{21}{4}-\cfrac{11}{3}\implies \stackrel{\textit{we'll use the LCD of 12}}{\cfrac{(3)21-(4)11}{12}}\implies \cfrac{63-44}{12}\implies \cfrac{19}{12}\implies 1\frac{7}{12}$