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2 years ago

Please help ! i really need it

Mathematics

1 answer:

BigorU [14]2 years ago

5 0

To solve the problem, we need to use the relation between the angles to find a relation involving x. Then we need to solve for x and use that value to determine the measure of the desired angle.

The diagram shows you ...

... ∠KIJ + ∠JIH = ∠KIH

The problem statement tells you ∠KIJ = ∠JIH, so we can substitute ∠JIH in the above equation to get

... ∠JIH + ∠JIH = ∠KIH

... (4x+3) + (4x+3) = (12x)

... 8x +6 = 12x

... 6 = 4x . . . . . . . subtract 8x

Since we want to know the value of 12x, we can go directly there

... 18 = 12x . . . . . . multiply the above equation by 3

m∠KIH = 18°

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Read 2 more answers

Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a

ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) $z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

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2 years ago

A factory that manufactures bolts is performing a quality control experiment. Each object should have a length of no more than c

disa [49]

Answer:

There is sufficient evidence. A further explanation is provided below.

Step-by-step explanation:

According to the question,

The alternative as well as null hypothesis will be:

$H_0:\mu = 16$

$H_a:\mu>16$

The test statistics will be:

⇒ $z = \frac{\frac{\bar x - \mu}{\sigma} }{\sqrt{n} }$

By putting the values, we get

⇒ $=\frac{\frac{16.06-16}{0.24} }{\sqrt{96} }$

⇒ $=\frac{\frac{0.06}{0.24} }{\sqrt{96} }$

⇒ $=2.45$

Or,

The p-value will be:

= 0.0071

i.e.,

⇒ $p-value< \alpha$

Thus the above is the correct answer.

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2 years ago

(-4,2) is a solution to the following graph. True or False?

emmasim [6.3K]

Plugging in the values of (-4,2) into the two inequality statements to see whether it is part of the solution to the inequality system:

y ≥ -5x + 3
2 ≥ -5(-4) + 3
2 ≥ 20 + 3
2 ≥ 23 (false statement).

For the other inequality statement, substitute 2 for the y value:

y > -2
2 > -2 (true statement).

Since (-4,2) only satisfies one of the inequality statements, then it means that it is not a solution to the graph.

Therefore, the correct answer is FALSE.

Please mark my answers as the Brainliest if you find my explanation helpful :)

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2 years ago