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balandron [24]
3 years ago
9

Blake's car has traveled 100 miles in 1 1/4 hours. How many mules per hour in Blake's car traveling?

Mathematics
1 answer:
n200080 [17]3 years ago
5 0

Answer:

Blake's car would be traveling at 80 mph

Step-by-step explanation:

100/1.25=80

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The point (-3, -5) is on the graph of a function. Which equation must be true regarding the function?
Alecsey [184]

Answer:

f(- 3) = - 5

Step-by-step explanation:

Given the point (- 3, - 5)

where x = - 3 is the input and y = - 5 is the output

The function can be represented by

y = f(x), that is

f(- 3) = - 5

3 0
4 years ago
Help ASAP please ...
cupoosta [38]

Answer:

Angle Q

Step-by-step explanation:

As I said on my previous posts, all you need to remember is CPCTC (corresponding parts of congruent triangles are congruent)

Q corresponds to B, and is thus congruent

8 0
3 years ago
Read 2 more answers
Find the missing side (X) round to the nearest hundredth
nata0808 [166]

Answer:

\displaystyle 18,28 ≈ x

Step-by-step explanation:

\displaystyle \frac{x}{11} = csc\:37 \hookrightarrow 11csc\:37 = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x

<em>OR</em>

\displaystyle \frac{11}{x} = sin\:37 \hookrightarrow xsin\:37 = 11 \hookrightarrow \frac{11}{sin\:37} = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x

Information on trigonometric ratios

\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ

I am joyous to assist you at any time.

7 0
2 years ago
Every morning, Lillian collects eggs from the hens on her family's farm. She puts the eggs in cartons of 16. On Monday, Lillian
Mars2501 [29]
Answer- D)11
37÷16=2 r5
16-5=11

5 0
3 years ago
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
Read 2 more answers
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