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attashe74 [19]
4 years ago
8

Solve: 3x + 18 - 7 = 41

Mathematics
1 answer:
solmaris [256]4 years ago
7 0

Answer:

x + 10

Step-by-step explanation:

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What is the volume of the cube below?
Doss [256]

Answer:

D. x^3

Step-by-step explanation:

1. Volume of cube = width*length*height

2. width, length, and height of a cube are all the same. In this case, it's x.

3. multiply x * x * x to get x^3

7 0
3 years ago
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Help me with this please
goldfiish [28.3K]

Answer:

12

Step-by-step explanation:

You need to use PEMDAS

No Parenthesis

4^2 is 16, since 4 * 4 = 16

Now the equation is 24 - 16 + 2*2

2 * 2 = 4

24 - 16 + 4

24 - 16 = 8

8 + 4 = 12

Hope this helps

6 0
3 years ago
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Un jardín rectangular de 50 cm de largo por 34 m de ancho está rodeado por un camino de arena uniforme.Halla la anchura de dicho
Anastasy [175]

Answer:

5.85 m

Step-by-step explanation:

The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

A_{g} = a.b

<u>Where:</u>

Ag: is the area of the rectangular garden

a: is the length of the rectangular garden = 50 cm = 0.5 m

b: is the width of the rectangular garden = 34 m

A_{s} = 540 m^{2}

<u>Where</u>:

As: is the area of the sand road

The relation between the area of the sand road and the area of the rectangular garden is the following:

A_{s} + A_{g} = (a+2x)*(b+2x)

540 m^{2} + 0.5m*34m = ab + 2ax + 2bx + 4x^{2}

557 m^{2} = ab + 2x(a + b) + 4x^{2}

557 m^{2} - 17m^{2} - 2x(34.5 m) - 4x^{2} = 0

540 - 69x - 4x^{2} = 0                              

By solving the above equation for x we have two solutions:

x₁ = -23.10 m

x₂ = 5.85 m

Taking the positive value, we have that the width of the sand road is 5.85 m.

I hope it helps you!

7 0
3 years ago
Which statement best describes the slope of the line?
Anton [14]

Answer:A

Step-by-step explanation:

6 0
3 years ago
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4(7-8n)=-2n+8(6-5n) point slope from
Viefleur [7K]

Answer:

n = 2 i beleve

Step-by-step explanation:

i dont know if this is right but i did the math and im in 6th grade so im not really good with that stuff

<3 have a good day <3

8 0
3 years ago
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