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Ivanshal [37]
3 years ago
15

A jumbo chocolate bar with a rectangular shape measures 11 centimeters in​ length, 8 centimeters in​ width, and 3 centimeters in

thickness. Due to escalating costs of​ cocoa, the management has decided to reduce the volume of the bar by 20​%. To accomplish this​ reduction, management decides that the new bar should have the same 3 centimeter​ thickness, but the length and width of each should be reduced by an equal number of centimeters. What should be the dimensions of the new candy​ bar?
Mathematics
1 answer:
jolli1 [7]3 years ago
3 0

11ce^3 nt^2 imrs, 8ce^3 nt^2 imrs, 3ce^3 nt^2 imrs, 0.2, 3ce^3 nt^2 imr, ce^3 nt^2 imrs

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You first need to know the equation A=pi x r^2. The equation you need for this problem is pi (3.14) x 3^2
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Write y – 3 = (x – 6) in standard form.
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Step-by-step explanation:

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Answer:

Should be A.

Step-by-step explanation:

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7 0
3 years ago
2. There is a 50% chance that Elaine will be late to school, a 40% chance that she will be late to
Verdich [7]

Answer:

50%

Step-by-step explanation:

Given that:

P(late) = P(L) = 50% = 0.5

P(Eat) = P(E) =?

P(LnE) = 40% = 0.4

P(LuE) = 60% = 0.6

P(LuE) = P(L) + P(E) - P(LnE)

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0.6 = 0.1 + x

0.6 - 0.1 = x

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8 0
3 years ago
11/6358 long agurithum
miss Akunina [59]

Answer:

Least common multiple:

lcm (578; 11) = 6,358 = 2 × 11 × 172;

Numbers have no common prime factors: 6,358 = 578 × 11.

Step-by-step explanation:

Approach 1. Integer numbers prime factorization:

578 = 2 × 172;

11 is a prime number, it cannot be broken down to other prime factors;

Multiply all the prime factors, by the largest exponents.

Least common multiple:

lcm (578; 11) = 2 × 11 × 172;

lcm (578; 11) = 2 × 11 × 172 = 6,358

Numbers have no common prime factors: 6,358 = 578 × 11.

Integer numbers prime factorization

Approach 2. Euclid's algorithm:

Calculate the greatest (highest) common factor (divisor), gcf, hcf, gcd:

Step 1. Divide the larger number by the smaller one:

578 ÷ 11 = 52 + 6; Step 2. Divide the smaller number by the above operation's remainder:

11 ÷ 6 = 1 + 5; Step 3. Divide the remainder from the step 1 by the remainder from the step 2:

6 ÷ 5 = 1 + 1; Step 4. Divide the remainder from the step 2 by the remainder from the step 3:

5 ÷ 1 = 5 + 0; At this step, the remainder is zero, so we stop:

1 is the number we were looking for, the last remainder that is not zero.

This is the greatest common factor (divisor).

Least common multiple, formula:

lcm (a; b) = (a × b) / gcf, hcf, gcd (a; b);

lcm (578; 11) =

(578 × 11) / gcf, hcf, gcd (578; 11) =

6,358 / 1 =

6,358;

lcm (578; 11) = 6,358 = 2 × 11 × 172;

8 0
3 years ago
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