All categories

3 years ago

17,254 to the nearest 1000

Mathematics

2 answers:

amm18123 years ago

6 0

17,254 to the nearest 1000

would be 17,000 because its not a big enough # to round up

EastWind [94]3 years ago

3 0

Your answer would be 17,000

You might be interested in

Which of the following is equal to 7 1/4?

marysya [2.9K]

Answer:

Step-by-step explanation:

$7^{\tfrac 14} = \sqrt[4]{7}$

4 0

2 years ago

How would you do this?

Bess [88]

It would be 6.0x4 because the square is 6.0 on each side

6 0

3 years ago

Read 2 more answers

Find each percent decrease of 80 to 64

Anastasy [175]

80-64=24
24 is 30% of 80 so a decrease of 30%

4 0

3 years ago

Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2

nlexa [21]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}$

$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

$\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}$

$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

2 years ago

Read 2 more answers

Plz help..................

Sever21 [200]

20mn - 30m
As you can see, both numbers are divisible by 10m. So if you were to divide them both, you would be left with, 10m (2n - 3), which would be the correct answer.

7 0

3 years ago