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3 years ago

Can someone answers this question please master it correctly if it’s corect I will mark you brainliest

Mathematics

1 answer:

Komok [63]3 years ago

5 0

Answer:

3 hits

Step-by-step explanation:

Out of 12 throws, Omar makes 2 hits

2/12 = simplify into 1/6

1/6 = x/18 Cross multiply

6x = 18 Divide 6 on both sides

x = 3

<h3><u><em>Hope this helps!!!</em></u></h3><h3><u><em>:p :)</em></u></h3>

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Let X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes. If the random vari

Gelneren [198K]

Answer:

Probability that the wait time is greater than 37 minutes is 0.3474.

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes.

<u><em>Let X = waiting time for a car to pass by on a country road</em></u>

The probability distribution function of exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} , x >0$ where, $\lambda$ = parameter of distribution.

Now, the mean of exponential distribution is = $\frac{1}{\lambda}$ which is given to us as 35 minutes that means $\lambda = \frac{1}{35}$ .

So, X ~ Exp( $\lambda = \frac{1}{35}$ )

Also, we know that Cumulative distribution function (CDF) of Exponential distribution is given as;

$F(x) = P(X \leq x) = 1 - e^{-\lambda x}$ , x > 0

Now, Probability that the wait time is greater than 37 minutes is given by = P(X > 37 min) = 1 - P(X $\leq$ 37 min)

P(X $\leq$ 37 min) = $1 - e^{-\frac{1}{35} \times 37}$ {Using CDF}

= 1 - 0.3474 = 0.6525

So, P(X > 37 min) = 1 - 0.6525 = 0.3474

Therefore, probability that the wait time is greater than 37 minutes is 0.3474.

4 0

3 years ago

PLEASSSSSE I NEED HELP BAD HELP PLEASE

charle [14.2K]

Answer:

See explanation

Step-by-step explanation:

Given the equation $3x-4y=12$

A. Create the table of values for at least 4 points.

When $x=0,$

$3\cdot 0-4y=12\\ \\-4y=12\\ \\y=-3$

When $x=2,$

$3\cdot 2-4y=12\\ \\-4y=12-6\\ \\-4y=6\\ \\y=-1.5$

When $x=4,$

$3\cdot 4-4y=12\\ \\-4y=12-12\\ \\-4y=0\\ \\y=0$

When $x=6,$

$3\cdot 6-4y=12\\ \\-4y=12-18\\ \\-4y=-6\\ \\y=1.5$

When $x=8,$

$3\cdot 8-4y=12\\ \\-4y=12-24\\ \\-4y=-12\\ \\y=3$

Thus, the table is

$\begin{array}{cc}x&y\\0&-3\\2&-1.5\\4&0\\6&1.5\\8&3\end{array}$

B. Use the table of values to graph the line on the coordinate plane. Plot given points and connect them with the straight line (see attached diagram).