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pantera1 [17]
3 years ago
15

A right rectangular prism is shown. What shape best describes the cross section cut perpendicular to the base of a right rectang

ular prism? Parallelogram Trapezoid Rectangle Square
Mathematics
2 answers:
GuDViN [60]3 years ago
5 0
The answer is C, Rectangle because if you think about it you are looking at a rectangular prism and you cut the cross - section perpendicular to the base of the right rectangular prism the shape will be a rectangle.
alisha [4.7K]3 years ago
4 0
Since the cross section is constrained to be perpendicular to the base, the shape of it is constrained to be a ...
  Rectangle

_____
That rectangle may be a square, but is not required to be.
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Hey all, can I get the answer + explanation for this? Would be much appreciated.
marysya [2.9K]

Answer:

x = 120

Step-by-step explanation:

Let's draw an imaginary dot in the middle of that <u>line</u> which runs between those two parallel lines, and now lets look at it as an angle.

This lines' angle is 180 degrees. Now lets move those two parallel lines together on the imaginary dot in the middle.

We can see that on the left side is one degree and the other side is another, however when we put them together we get the angle measurement of the our line which we identified was 180.

Now that we can see that our two angles must equal 180 when put together we know and can say that:

40 + (x + 20) = 180

So, lets work this out like basic algebra now.

40 + x + 20 = 180

       x + 60 = 180

           - 60   - 60

               x = 120

And voila we have our x value.

Hope this helps :)

4 0
3 years ago
In ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45. What is the value of the cosine of ∠X to the nearest hundredth?
kotegsom [21]

The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

Step-by-step explanation:

The given is,

                   In ΔWXY, ∠Y=90°

                        XW = 53

                         YX = 28

                        WY = 45

Step:1

             Ref the attachment,

             Given triangle XWY is right angled triangle.

             Trigonometric ratio's,

                              Cos ∅  = \frac{Adj}{Hyp}    

             For the given attachment, the trigonometric ratio becomes,

                              Cos ∅  = \frac{XY}{XW}.....................................(1)

             Let, ∠X = ∅

             Where, XY = 28

                         XW =  53

             Equation (1) becomes,

                                 Cos ∅  = \frac{28}{53}

                                 Cos ∅ = 0.5283

                                        ∅ = cos^{-1} (0.5283)

                                        ∅ = 58.109°

Result:

          The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

             

4 0
3 years ago
Happy holdiays everyone!
Sloan [31]

Answer:

Step-by-step explanation:Same to you !

4 0
3 years ago
Adam is taking out a $197,000 mortgage. His bank offers him an APR of 4.45%. He wants to compare monthly payments on a 15- and 3
xxMikexx [17]
The answer would be A. 509.68
4 0
3 years ago
PLZ ANSWER PLZ PLZ PLZ HELP 1 QUESTION!!!
JulsSmile [24]

We first must find the value of angle z.


Angle z = 90° - 42°


Angle z = 48°


We now use the sine function to find y.


sin(48°) = 35/y


y = 35/sin(48°)


y = 47.0971455362


We now round off to two decimal places.


y = 47.10


I hope this helps....



8 0
3 years ago
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