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pantera1 [17]
3 years ago
15

A right rectangular prism is shown. What shape best describes the cross section cut perpendicular to the base of a right rectang

ular prism? Parallelogram Trapezoid Rectangle Square
Mathematics
2 answers:
GuDViN [60]3 years ago
5 0
The answer is C, Rectangle because if you think about it you are looking at a rectangular prism and you cut the cross - section perpendicular to the base of the right rectangular prism the shape will be a rectangle.
alisha [4.7K]3 years ago
4 0
Since the cross section is constrained to be perpendicular to the base, the shape of it is constrained to be a ...
  Rectangle

_____
That rectangle may be a square, but is not required to be.
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PLS HELP ASAP ILL GIVE BRAINLKEST THANKS 10 POINTS
Anestetic [448]

#5 Option B

y=(5/4)(4)

= 20/4

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#6 Option B

y=2(1)

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5 0
3 years ago
Find 45% of 60 with work
Ilya [14]
Step 1. convert 45% into a decimal value
45% = 0.45

step 2. multiply the decimal value with the main number
0.45 *60

step 3.  ???

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The smallest composite number that can be written as a product of 4 different prime number are
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8 0
3 years ago
-2(x+4)<br> Help find answers
MAVERICK [17]
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3 years ago
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ANSWER ASAP PLZ!!
Vikentia [17]

\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}

Answer:

\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}

0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}

--------------------------------------------------------------------------

\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right

Answer:

\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}

2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}

7 0
4 years ago
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