2.7 • 2 because it’s twice a day. He’s waking 5.4 miles daily, 5.4 • 360 = 1,944 miles yearly.

Get x to one side
So minus 90 from each side

-90÷-3=30
Answer: x=30
Answer:
281 servings
Step-by-step explanation:
From the table attached,
We will apply the unitary method to solve this problem.
∵ 12.6 oz of chicken represents number of servings = 2
∴ 1 oz of chicken will represents number of servings =
∴ 1774.4 oz of chicken will make the total servings = 
= 281.65
≈ 281 servings
Therefore, total number of servings provided = 281
Answer;
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
Step-by-step explanation:
The complete question is as follows;
For 100 births, P(exactly 56 girls = 0.0390 and P 56 or more girls = 0.136. Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less V so 56 girls in 100 birthsa significantly high number of girls because the relevant probability is The relevant probability is 0.05
Solution is as follows;
Here. we want to know which of the probabilities is relevant to answering the question and also if 56 out of a total of 100 is sufficient enough to provide answer to the question.
Now, to answer this question, it would be best to reach a conclusion or let’s say draw a conclusion from the given information.
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
140/100 * 65 = 91 people
Divide 140 by 100 to find 1 percent then multiply by 65 to find 65 percent.