<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B3x%5E-3y%5E4%7D%7B5x%5E6y%5E7%20%7D%29%5E-2" id="TexFormula1" title="(\frac{3x^-3

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Jlenok [28]

3 years ago

y^4}{5x^6y^7 })^-2" alt="(\frac{3x^-3y^4}{5x^6y^7 })^-2" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

viktelen [127]3 years ago

7 0

9514 1404 393

Answer:

(25/9)x^18·y^6

Step-by-step explanation:

Maybe you want this simplified.

The appropriate rules of exponents are ...

(a^b)/(a^c) = a^(b-c)

(a^b)^c = a^(bc)

$\left(\dfrac{3x^{-3}y^4}{5x^6y^7}\right)^{-2}=\left(\dfrac{3x^{-3-6}y^{4-7}}{5}\right)^{-2}=\dfrac{3^{-2}}{5^{-2}}\cdot x^{(-2)(-9)}y^{(-2)(-3)}\\\\=\boxed{\dfrac{25}{9}x^{18}y^{6}}$

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valentinak56 [21]

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Step-by-step explanation:

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