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Jlenok [28]
3 years ago
8

y^4}{5x^6y^7 })^-2" alt="(\frac{3x^-3y^4}{5x^6y^7 })^-2" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
viktelen [127]3 years ago
7 0

9514 1404 393

Answer:

  (25/9)x^18·y^6

Step-by-step explanation:

Maybe you want this simplified.

The appropriate rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

__

  \left(\dfrac{3x^{-3}y^4}{5x^6y^7}\right)^{-2}=\left(\dfrac{3x^{-3-6}y^{4-7}}{5}\right)^{-2}=\dfrac{3^{-2}}{5^{-2}}\cdot x^{(-2)(-9)}y^{(-2)(-3)}\\\\=\boxed{\dfrac{25}{9}x^{18}y^{6}}

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