As θ increases from -pi/2 to 0 radians, the value of cos θ will.

Mathematics

1 answer:

GrogVix [38]2 years ago

8 0

Answer:

4) Increase from 0 to 1

Step-by-step explanation:

We have to analyze the value of cos(Ф) from -π/2 to 0. This can be done if we simplify evaluate the value of cos(Ф) at these two extreme.

$cos(-\frac{\pi}{2}) = cos(\frac{\pi}{2} )=cos(90)=0\\\\ cos(0)=1$

This shows that value of cos(Ф) is 0 at -π/2 or -90 degrees and increased to 0 at 0 degrees.

This answer can be validated if you visualize the graph of cos function. Cos function has a peak at 0 degrees, i.e. a value equal to 1. On right and left side of 0 degrees, the curve starts falling down and eventually touches the horizontal axis at 90 degrees and -90 degrees. This is shown in the graph attached below:

You might be interested in

-40-8b=-6(1+7b) what’s the answer

Andre45 [30]

$\text{Hey there!}$

$\mathsf{-40-8b=-6(1+7b)}\\\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}\\\mathsf{-40-8b=-6(1+7b)}$

$\mathsf{Distribute\ the\ RIGHT\ side\ of\ the\ equation }\\\mathsf{Distribute [the\ formula\ is: a(b+c)=a(b)+a(c)=ab+ac]}\\\mathsf{-6(1)+(-6)}(7b)\\\mathsf{-6(1)=-6}\\\mathsf{-6(7b)=-42b}\\\mathsf{\rightarrow\ =-6+(-42b)}$

$\mathsf{-40-8b=-6+(-42b)}\\\mathsf{\rightarrow -8b-40=-42b-6}$

$\mathsf{ADD\ by\ 42b\ on\ your\ sides}\\\mathsf{-8b-40+42b=-42b-6+42b}\\\mathsf{SOLVE\ above\ correct\ to\ get\ us\ to\ the\ next\ step!}\\\mathsf{\rightarrow 34b-40=-6}$

$\mathsf{ADD\ by\ 40\ on\ your\ sides}\\\mathsf{34b-40+40=-6+40}\\\mathsf{Cancel\ out\ -40+40\ because\ that\ gives\ the\ result\ of\ 0}\\\mathsf{-6+40=34}\\\mathsf{\rightarrow New\ equation: 34b = 34}$

$\mathsf{DIVIDE\ both\ of\ your\ sides\ by\ 34}\\\mathsf{\dfrac{34b}{34}=\dfrac{34}{34}}\\\\\mathsf{Cancel\ out: \dfrac{34b}{34}\ because\ that\ gives\ you\ the\ result\ of\ 1b}\\\\\mathsf{Keep:\dfrac{34}{34}\ because\ it\ solves\ for\ b}\\\\\mathsf{\dfrac{34}{34}=34\div34=1}$