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Dmitry [639]
3 years ago
7

Need help fast right now. Find the surface area of each solid. Round to the nearest tenth of necessary.

Mathematics
1 answer:
Mice21 [21]3 years ago
7 0

Answer:

5)surface =2(lb*bh*hl)

=2(12*4+4*4+4*12)

=2(48+16+48)

=2(96+16)

=2*112

=224inc^2

6)surfacearea=2*pi*r(r+h)

=2*3.14*2(2+1)

=6.28*2*3

=6.28*6

=37.68m^2

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What is 2 + v/2 = -2?
Artemon [7]

Answer:

v = -8

Step-by-step explanation:

2 + v/2 = -2

Subtract 2 from each side

2-2 + v/2 = -2-2

v/2 =-4

Multiply each side by 2

v/2*2 = -4*2

v = -8

3 0
2 years ago
Solve: 8+ x/2 = 1/4(x-4)-1
dangina [55]

Answer:

D the answer is -40

Step-by-step explanation:

6 0
2 years ago
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Which equivalent expression would you set up to verify the associative property of addition for (3x + 4) + ((5x2 – 1) + (2x + 6)
saw5 [17]

(3x+4)+(5x2-1)+(2x+6)

remove unnecessary parenthesis

3x+4+(5x2-1)+(2x+6)

3x+4+(10-1)+2x+6

subtract the numbers

3x+4+9+2x+6

collect the like terms

5x+4+4+9+6

5x+19

4 0
3 years ago
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How many x intercept appear on the graph of the polynomial function F(x)=x4-5x2
4vir4ik [10]
f(x)=x^4-5x^2\\\\x^4-5x^2=0\\\\x^2(x^2-5)=0\\\\x^2[x^2-(\sqrt5)^2]=0\\\\x^2(x-\sqrt5)(x+\sqrt5)=0\iff x=0\ \vee\ x=\sqrt5\ \vee\ x=-\sqrt5

Answer: 3 x-intercepts.

3 0
3 years ago
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
3 years ago
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