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3 years ago

Need help fast right now. Find the surface area of each solid. Round to the nearest tenth of necessary.

Mathematics

1 answer:

Mice21 [21]3 years ago

7 0

Answer:

5)surface =2(lb*bh*hl)

=2(12*4+4*4+4*12)

=2(48+16+48)

=2(96+16)

=2*112

=224inc^2

6)surfacearea=2*pi*r(r+h)

=2*3.14*2(2+1)

=6.28*2*3

=6.28*6

=37.68m^2

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11. Charles's Law states that at constant pressure, the volume of a fixed amount of gas varies

Zanzabum

Answer:

a.V=5/6T

b. 350 ml

Step-by-step explanation:

V∝T

or V=kT

where k is a constant.

V=250 ml

T=300° K

250=300 k

k=250/300=5/6

so V=5/6 T

V=5/6 T

=5/6×420

=5×70

=350 ml

6 0

3 years ago

ExtremeBDS [4]

It’s 13.1 ft I know cause I did the math all the way it’s 13.1 so yeah

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=10-%5Cfrac%7B3y-1%7D%7B2%7D%20%3D%5Cfrac%7B6y%2B3%7D%7B11%7D" id="TexFormula1" title="10-\frac

Ghella [55]

$10-\frac{3x-1}{2} =\frac{6x+3}{11}$

$10 = \frac{6x+3}{11} + \frac{3x-1}{2}$

$10 = (\frac{6x+3}{11} \times \frac{2}{2} ) + (\frac{3x-1}{2} \times \frac{11}{11} )$

$10 = ( \frac{2(6x + 3)}{22} ) + ( \frac{11(3x - 1)}{22} )$

$10 = \frac{12x + 6}{22} + \frac{33x - 11}{22}$

$10 = \frac{12x + 6 + 33x - 11}{22}$

$10 = \frac{(12 x + 33x) + (6 - 11)}{22}$

$10 = \frac{45x - 5}{22}$

$10 \times 22 = 45x - 5$

$220 = 45x - 5$

$220 + 5 = 45x$

$225 = 45x$

$\frac{225}{45} = x$

$\frac{45}{9} = x$

$5 = x$

7 0

2 years ago

Pls help I really don’t understand I’ll be thankful thanks and no links

inysia [295]

Answer:

A: Right

B: Acute

C: Obtuse

D: Acute

Step-by-step explanation:

A: Right

(90 degrees)

B: Acute

(less than 90)

C: Obtuse

(over 90 degrees)

D: Acute

(less than 90)

6 0

3 years ago

Describe the process of rewriting the expression Please Help

Mazyrski [523]

Answer:

$x^{\frac{21}{4} }$

Step-by-step explanation:

Given expression is:

$(\sqrt[8]{x^7} )^{6}$

First we will use the rule:

$\sqrt[n]{x} = x^{\frac{1}{n} }$

So for the given expression:

$\sqrt[8]{x^{7}}=(x^{7} )^{\frac{1}{8} }$

We will use tha property of multiplication on powers:

$=x^{7*\frac{1}{8} }$

$= x^{\frac{7}{8} }$

Applying the outer exponent now

$(x^{\frac{7}{8} })^6$

$= x^{\frac{7}{8}*6 } \\= x^{\frac{42}{8} }\\= x^{\frac{21}{4} }$

8 0

3 years ago