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Sunny_sXe [5.5K]
3 years ago
5

A bank is offering you an introductory credit card promotion. Your interest for the first year is 8%. But, at the beginning

Mathematics
1 answer:
Art [367]3 years ago
7 0

Answer:

  • c) $22.50

Explanation:

<u>1. Calculate the monthly interest owed during year 1</u>

<u />

  • <em>Interest for first year: 8%</em>

  • The monthly rate is the yearly rate divided by 12: 8% / 12 = 0.08/12

  • The monthly interest owed is the monthly rate times the balance: (0.08/12)×$1,800 = $12.00

<u>2. Calculate the monthly interest owed during year 2</u>

<u />

  • <em>Interest for second year: 23%</em>

  • The montly rate is the yearly rate divided by 12: 23% / 12 = 0.23/12

  • The monthly interest owed is the monthly rate times the balance: (0.23/12)×$1,800 = $34.50

<u>3. Calculate the difference</u>

  • Difference in the monthly interest owed during year 1 and year 2 = $34.50 - $12.00 = $22.50

Hence, the answer is the option c) $22.50

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Answer:

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Step-by-step explanation:

If you have 2 people working and need to know how long it would take them to finish a job. Working together on the same job, you add each of their total hours to do the job alone,, 5 + 3 = 8, then divide the 8 by 2 people

equals 4 hours for 2 people on 1 job.

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3 years ago
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Step-by-step explanation:

A)y=8

B)k=10

5y=72-32

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Please help, I really need help<br> Will mark as brainliest....
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Answer:

Step-by-step explanation:

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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
2 years ago
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