All categories

2 years ago

Find the slope of the line passing through the points (-7,2) and (9,6)

Mathematics

2 answers:

ArbitrLikvidat [17]2 years ago

7 0

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-7, 2) and (9, 6). Substitute:

$m=\dfrac{6-2}{9-(-7)}=\dfrac{4}{16}=\dfrac{1}{4}$

<h3>Answer: The slope = 1/4</h3>

rewona [7]2 years ago

4 0

Answer:

1/4

Step-by-step explanation:

So the slope of a line is the change in y over the change in x. So that would be 4/16 or 1/4

You might be interested in

Jill has 4 bags of marbles. There are 3red, 5green,2 yellow, and 6black marbles I. Each bag. How many marbles does Jill have? Sh

Eddi Din [679]

3+5+2+6=16 in each bag multiply or divide sorry not that much of an answer

6 0

2 years ago

Read 2 more answers

100 POINTS!! HELP!!!! BRAINLIEST ANSWER

Black_prince [1.1K]

The turning point is (3,3). The x to make the absolute value negative would be 2. The ordered pair would then be (0,3)

8 0

2 years ago

Read 2 more answers

Which expression is a factor of this polynomial x^3+2x^2-9x-18

REY [17]

Answer: (x+2)

Step-by-step explanation:

4 0

3 years ago

Reduce to simplest form. <br> -7/12 +3/8

gayaneshka [121]

Answer:

ok so you should get -5/24 in simplest form.

Decimal form- -0.2083 repeating

Step-by-step explanation:

Hope this helped :)

4 0

2 years ago

a plane flying with the wind travels 630 mi in 1.5hrs. Flying against the wind , the plane travels 1120 mi in 4hrs. Find the rat

Flauer [41]

$\bf \begin{cases}
r=\textit{rate of the plane}\\
w=\textit{rate of the wind}\\
\end{cases}
\\\\

\begin{array}{ccccllll}
&distance&rate&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
\textit{with wind}&630&r+w&1\frac{1}{2}\\
\textit{against wind}&1120&r-w&4
\end{array}
$

$\bf thus \begin{cases}
630=(r+w)1\frac{1}{2}\to 630=(r+w)\frac{3}{2}
\\\\
1120=(r-w)4\\
--------------\\
630=(r+w)\frac{3}{2}\implies 630\cdot \frac{2}{3}=r+w\\
420=r+w\implies \boxed{420-w}=r\\
--------------\\
thus\\
--------------\\
1120=(r-w)4\implies 1120=4r-4w
\\\\
1120=4(\boxed{420-w})-4w
\end{cases}
$

solve for "w", to find the wind's speed rate,

so hmmm what's the plane's rate? well 420 - w = r :)

5 0

2 years ago