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Arada [10]
3 years ago
14

The mass of 3.45 L of hydrogen gas at SATP

Chemistry
1 answer:
Licemer1 [7]3 years ago
5 0

Answer:

Explanation:

The easy way is knowing that all gases basically are 22.4 L/mol at SATP.

There fore   3.45 L/22.4 L/mol =0.154 mol

Or use PV=nRT

n=(1 atm)(3.45L)/(273 K)(0.82 L atm)/(mol K) =0.154 mol

same answer

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3 0
3 years ago
PLEASE HELP! WILL MARK BRAINIEST IF ANSWERED CORRECTLY.
ioda

Answer:

H2O is a polar molecule

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Explanation:

3 0
3 years ago
25 points please help
maxonik [38]

Answer : Option (A) Accelerator 2 model has the lowest percentage of energy lost as waste.

Solution : Given,

For Accelerator 1 model,

Input energy = 2078.3 J

Wasted energy = 663.1 J

Output energy = 1415.2 J

For Accelerator 2 model,

Input energy = 7690.0 J

Wasted energy = 2337.5 J

Output energy = 5353.5 J

For Accelerator 3 model,

Input energy = 4061.9 J

Wasted energy = 2259.6 J

Output energy = 1802.3 J

Formula used for lowest percentage of energy lost as waste is:

% energy lost as waste = (Total energy wasted / Total input energy )  ×  100

For Accelerator 1 model,

% energy lost as waste = \frac{663.1}{2078.3}\times100 = 31.90%

For Accelerator 2 model,

% energy lost as waste = \frac{2337.5}{7690.0}\times100 = 30.39%

For Accelerator 3 model,

% energy lost as waste = \frac{2259.6}{4061.9}\times100 = 55.62%

So, we conclude that the Accelerator 2 model has the lowest percentage of energy lost as waste.



6 0
3 years ago
How many grams of calcium carbonate, CaCO3, contain 48 grams of oxygen atoms?
Tamiku [17]

Answer:

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7 0
3 years ago
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