Answer is: <span>the maximum mass of sugar that could be dissolved in 1.3 l of water in room temperature is 2652 grams.
</span><span>The solubility of sugar in water in room temperature is 204 g/100 ml.
Make proportion, if 204 grams of sugar dissolve in 100 ml of water, than how much dissolve in 1300 ml of water:
204 g : 100 ml = m(sugar) : 1300 ml.
m(sugar) = 204 g </span>· 1300 ml ÷ 100 ml.
m(sugar) = 2652 g ÷ 1000 g/kg = 2,652 kg.
Hey there!
K₂Te + Fe(HCO₃)₂ → KHCO₃ + Fe + Te
Start by balancing HCO₃ since it's a polyatomic ion.
Two on the left, one on the right. Add a coefficient of 2 in front of KHCO₃.
K₂Te + Fe(HCO₃)₂ → 2KHCO₃ + Fe + Te
Balance K .
Two on the left, two on the right. Already balanced.
Balance Te.
One on the left, one on the right. Already balanced.
Balance Fe.
One on the left, one on the right. Already balanced.
Our final balanced equation:
K₂Te + Fe(HCO₃)₂ → 2KHCO₃ + Fe + Te
Hope this helps!
Answer:
#2.
Explanation:
Look at the charges. Both are positive, therefore both are cations.
Answer:
See explanation
Explanation:
In this question, we have to follow the IUPAC rules. Lets analyze each compound:
a. 1-methylbutane
In this compound we have a chain of 5 carbons, so the correct name is <u>Pentane.</u>
b. 1,1,3-trimethylhexane
In this compound, we longest chain is made of 7 carbons, so, we have to use the name "heptane". Carbon one would be the closet one to the methyl group, so the correct name is <u>2,4-dimethylheptane.</u>
c. 5-octyne
In this case, carbon 1 would be the closet one to the triplet bond. With this in mind, the correct name is <u>oct-3-yne.</u>
d. 2-ethyl-1-propanol
In this compound, we longest chain is made of 4 carbons, so, we have to use the name "butane". Carbon one would be the carbon with the "OH" group, so the correct name is <u>2-methylbutan-1-ol.</u>
<u>e. 2.2-dimethyl-3-butanol</u>
In this case, carbon 1 would be the closet one to the "OH". With this in mind, the correct name is <u>3,3-dimethylbutan-2-ol.</u>
See figure 1
I hope it helps!