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Rina8888 [55]
3 years ago
8

An electric iron is used to remove wrinkles from clothing. The electric iron is made of metal. Which property of this substance

is most useful for this application?
a boiling point

b density

c electrical conductivity

d thermal conductivity
Chemistry
2 answers:
Verdich [7]3 years ago
8 0

The correct option is D.

Metals have different properties which are utilized in diverse ways to meet the need of man. One of the properties of metals is thermal conductivity. Thermal conductivity refers to the ability of the metal to conduct heat. This property is especially useful in the working of electric pressing iron. The heat released by the metal that is used in the manufacturing of the iron is regulated by mean of thermostat, which keep the heat constant in order to protect the clothes been ironed from damage.

aleksley [76]3 years ago
5 0
It would most likely be D. Thermal conductivity, as the metal used in ironing is able to conduct heat and allow ironing to be done.
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An empty vial weighs 55.32 g.
ziro4ka [17]

The answer is: Volume of mercury = 9.63 cm^3.

Density (d) is defined as mass of substance divided by its volume. Thus, if mass and density are known, then Volume can be determined.

What is the formula of volume in terms of density?

  • Let mass of substance be 'm' and volume be 'V'. Thus, as per the definition of density, it is expressed as-

d =\frac{m}{V}

  • Thus, volume can be expressed as-

V = \frac{m}{d}

  • Now, mass of empty vial= 55.32 g and the mass of  (vial+ mercury) = 185.56 g.

Thus, mass of mercury =185.56\ g- 55.32\g = 130.24\ g

  • Thus, mass of mercury = 130.24 g and density of mercury =13.53\ g/cm^3. Its volume is calculated as-

V =\frac{130.24\ g}{13.53\ g/cm^3}  = 9.63\ cm^3

  • Hence, volume of mercury = 9.63 cm^3.

To learn more about Density and Volume, visit:

brainly.com/question/1028144

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It transferred from electrical to sound.
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(2 KClO3 (s) → 2 KCl (s) + 3 O2 (g) ) If 165 mL of oxygen is produced at 30.0 °C and 90.0 kPa, what mass of KClO3 was decomposed
soldier1979 [14.2K]

Taking into account the reaction stoichiometry and ideal gas law, 0.48144 grams of KClO₃ was decomposed.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 KClO₃  → 2 KCl + 3 O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • KClO₃: 2 moles  
  • KCl: 2 moles
  • O₂: 3 moles

The molar mass of the compounds is:

  • KClO₃: 122.45 g/mole
  • KCl: 74.45 g/mole
  • O₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • KClO₃: 2 moles ×122.45 g/mole= 244.8 grams
  • KCl: 2 moles ×74.45 g/mole= 148.9 grams
  • O₂: 3 moles ×32 g/mole= 96 grams

<h3>Ideal gas law</h3>

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

  • P is the gas pressure.
  • V is the volume that the gas occupies.
  • T is the temperature of the gas.
  • R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
  • n is the number of moles of the gas.

<h3>Number of O₂ produced.</h3>

165 mL of oxygen is produced at 30.0 °C and 90.0 kPa. This is, you know:

  • P= 90 kPa= 0.888231 atm (being 101.325 kPa= 1 atm)
  • V= 165 mL= 0.165 L (being 1000 mL= 1 L)
  • n= ?
  • R= 0.082 \frac{atmL}{molK}
  • T= 30 C= 303 K (being 0 C= 273 K)

Replacing in the ideal gas law:

0.888231 atm× 0.165 L = n× 0.082 \frac{atmL}{molK}× 303 K

Solving:

n= (0.888231 atm× 0.165 L)÷ (0.082 \frac{atmL}{molK}× 303 K)

<u><em>n= 0.0059 moles</em></u>

Finally, 0.0059 moles of oxygen is produced at 30 °C and 90 kPa.

<h3>Mass of KClO₃ required</h3>

The following rule of three can be applied: If by stoichiometry of the reaction 3 moles of O₂ are produced by 244.8 grams of KClO₃, 0.0059 moles of O₂ are produced by how much mass of KClO₃?

mass of KClO_{3}= \frac{0.0059 moles of O_{2}x 244.8 grams of KClO_{3}}{3 moles of O_{2}}

<u><em>mass of KClO₃= 0.48144 grams</em></u>

Finally, 0.48144 grams of KClO₃ was decomposed.

Learn more about

the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

ideal gas law:

<u>brainly.com/question/4147359?referrer=searchResults</u>

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2 years ago
Why don't noble gasses want to react with anyone?
Zepler [3.9K]
They have a full valence shell (8 electrons in the outer shell) so they are the most stable elements on the periodic table. Therefore, they do not need to react to other elements to gain or lose elections to become stable. 
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3 years ago
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