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Rina8888 [55]
3 years ago
8

An electric iron is used to remove wrinkles from clothing. The electric iron is made of metal. Which property of this substance

is most useful for this application?
a boiling point

b density

c electrical conductivity

d thermal conductivity
Chemistry
2 answers:
Verdich [7]3 years ago
8 0

The correct option is D.

Metals have different properties which are utilized in diverse ways to meet the need of man. One of the properties of metals is thermal conductivity. Thermal conductivity refers to the ability of the metal to conduct heat. This property is especially useful in the working of electric pressing iron. The heat released by the metal that is used in the manufacturing of the iron is regulated by mean of thermostat, which keep the heat constant in order to protect the clothes been ironed from damage.

aleksley [76]3 years ago
5 0
It would most likely be D. Thermal conductivity, as the metal used in ironing is able to conduct heat and allow ironing to be done.
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A 200.0 mL solution of 0.40 M ammonium chloride was titrated with 0.80 M sodium hydroxide. What was the pH of the solution after
choli [55]

Answer:

9.25

Explanation:

Let first find the moles of NH_4Cl and NaOH

number of moles of NH_4Cl = 0.40  mol/L × 200 ×  10⁻³L

= 0.08 mole

number of moles of NaOH = 0.80  mol/L × 50 ×  10⁻³L

= 0.04 mole

The equation for the reaction is expressed as:

NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

The ICE Table is shown below as follows:

                            NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

Initial (M)              0.08            0.04                            0

Change (M)         - 0.04          -0.04                          + 0.04

Equilibrium (M)      0.04             0                                0.04

K_a*K_b = 10^{-14} \ at \ 25^0C

K_a = \frac{10^{-14}}{K_b}

K_a = \frac{10^{-14}}{1.76*10^{-5}}

K_a= 5.68*10^{10}

pK_a = - log \ (K_a)

pK_a = - log \ (5.68*10^{-10})

pK_a = 9.25

pH = pKa + \ log (\frac{HB}{HA} )   for buffer solutions

pH = pKa + \ log (\frac{moles \ of \ base }{ moles\ of \ acid} ) since they are in the same solution

pH = 9.25 + \ log (\frac{0.04 }{ 0.04} )

pH = 9.25

8 0
3 years ago
Based on your solubility rules which of the following compounds would form a precipitate water?
Novosadov [1.4K]
H2SO4+NaOH=Na2SO4+H2O
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