Answer:
56 Cola-flavored gumballs remaining.
Step-by-step explanation:
There are 180 gumballs. Bob purchased 40 gumballs, which leaves 140 gumballs remaining.
There are four flavors. This is the chance (shown as a percentage) of each flavor Bob recieved:
║GR: 4 ⇒ 10%
║CH: 12 ⇒ 30%
║CO: 16 ⇒ 40%
║OR: 8 ⇒ 20%
So, how can we predict the number of Cola flavored gumballs remaining?
[<em>There is a 40% chance of getting a Cola-flavored gumball from the machine. If we find 40% of 140, we can predict that is close to the number of Cola gumballs left in the machine</em>]
║0.40 ⋅ 140 = 56
40% of 140 is 56, so we can predict there are 56 Cola-flavored gumballs remaining.
Answer:
0
Step-by-step explanation:
srry if it's wrong :/
Answer:
false i think
Step-by-step explanation:
Answer:
13. 8 cm
Step-by-step explanation:
For the fifth sharpshooter to win, her average should be at most 3.4 since the best so far is 3.5.
so the equation would be
(3.2+x)/5=3.4
3.2+x=3.4×5
3.2+x=17
x= 17 - 3.2
x= 13.8
1) 4x
2) 2x+3z=5z
=5z+5
3) I can't see problem number 3.
4) 9g+8g=17g
5) 5p-p=4p
=4p-8
6) Cant see problem number 6.
7) 4x-x= 3x 3y+2y
=3x+5y
8) 5x+4x= 9x 2y-y=y
=9x+y
9) Can't see problem number 9.
10) 7p+2p=9p 5z-2z=3z
=9p+3z
11) 7g+5h-12
12) Can't see problem number 12.
13) 3(r+2)-2r
3r+6-2r
=r+6
14) 5(2+x)+3x
10+5x+3x
=10+8x
15) Can't see problem number 15.