(x-3)^2 + (x+5)^2=9^2
(x^2-6x+9) + (x^2+10x+25)=81
2x^2+4x+34=81
2x^2+4x-47=0
From here just use quadratic formula
Answer:
It is A
Step-by-step explanation:
Equation: 5x+1=9+3x
5x+1=9+3x
-1 -1
_________
5x=8+3x
-3x -3x
________
2x=8
__ __
2 2
<h2><u><em>
x=4</em></u></h2>
Answer:
<h3>
a = (2mz - 3m)/4</h3>
Step-by-step explanation:
2z = 4a/m +3
-3 -3
2z - 3 = 4a/m
×m ×m
(2z -3)m = 4a
÷4 ÷4
[(2z -3)m]/4 = a
a = (2mz - 3m)/4
Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
P = 2L + 2w
Subtract 2L
from each side: P - 2L = 2w
Divide each side
by 2 : (P - 2L) / 2 = w
You could also write it as (P/2 - L) = w
Both answers are the same.
