First you need to distribute the exponent into the terms for the first parenthesis.
(-3x²y³)³ = (-3)³ * (x²)³ * (y³)³
= -27 *x⁶ *y⁹
= -27x⁶y⁹
Then you multiply -27x⁶y⁹ by x²y.
You just need to add the exponents of x and y:
-27x⁶⁺²y⁹⁺¹
= -27x⁸y¹⁰
77+72=149
149/2=74.5
through the process of elimination, I found that Jim needs to get an 88 or higher to receive an average of 79 or greater.
77+72+88=237
237/3=79
Answer: c. 8!
Step-by-step explanation:
We know , that if we line up n things , then the total number of ways to arrange n things in a line is given by :-
( in words :- n factorial)
Therefore , the number of ways 8 cars can be lined up at a toll booth would be 8! .
Hence, the correct answer is c. 8! .
Alternatively , we also use multiplicative principle,
If we line up 8 cars , first we fix one car , then the number of choices for the next place will be 7 , after that we fix second car ,then the number of choices for the next place will be 6 , and so on..
So , the total number of ways to line up 8 cars = 8 x 7 x 6 x 5 x 4 x 3 x 2 x1 = 8!
Hence, the correct answer is c. 8! .
Answer:
see explanation
Step-by-step explanation:
The n th term of a geometric sequence is
= a
where a is the first term and r the common ratio
Given
=
and r =
, then
a
=
, that is
= 
=
( cross- multiply )
32a = 2048 ( divide both sides by 32 )
a = 64 ← first term
Thus the explicit formula is
= 64 