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vekshin1
3 years ago
14

Which statement best explains water’s ability to dissolve covalent compounds? a. Water can dissolve polar covalent compounds thr

ough dipole-dipole interactions. b. Water can dissolve nonpolar covalent compounds through hydrogen-bonding interactions. c. Water can dissolve polar covalent compounds through ion-dipole interactions. d. Water can dissolve nonpolar covalent compounds through dipole-dipole interactions.
Chemistry
2 answers:
Ilya [14]3 years ago
6 0
"c. Water can dissolve polar covalent compounds through ion-dipole interactions" is the statement that best explains water’s ability to dissolve covalent compounds.
Liula [17]3 years ago
3 0

<u>Answer:</u> The correct answer is Option a.

<u>Explanation:</u>

A covalent compound is defined as a compound which is formed by the sharing of electrons between the atoms. These are of two types: Polar covalent compound and non-polar covalent compound.

Water is a polar covalent compound.

In polar covalent compound, a dipole is present and when this compound interacts with another polar covalent compound, it is bonded with dipole-dipole interactions. Thus, a polar covalent compound can be easily dissolved in another polar covalent compound.

A non-polar covalent compound cannot be dissolved in a polar covalent compound because of the difference in polarity.

Ion-dipole interactions occur when an ionic compound interacts with a dipole.

Hence, the correct answer is Option a.

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valkas [14]

Explanation:

KMnO4 + H2S + HCl --> KCl + MnCl2 + H2O + S8

Did Cl change oxidation number?

The oxidation  number of Cl in Reactant side is -1

The oxidation number of Cl in product side is -1

NO

Did Oxygen change oxidation number?

The oxidation number of O in Reactant side is -2

The oxidation number of O in product side is -2

NO

Did H change oxidation number?

The oxidation number of H in Reactant side is 1

The oxidation number of H in product side is 1

NO

Did Mn change oxidation number?

The oxidation number of Mn in Reactant side is +7

The oxidation number of Mn in product side is +2

YES

Did S change oxidation number?

The oxidation number of S in Reactant side is -2

The oxidation number of S in product side is 0

YES

Oxidizing agent (element with decrease in oxidation number) = Mn

Reducing agent (element with Increase in oxidation number) = S

4 0
3 years ago
What are use of ammonical liquor​
denis-greek [22]

ammoniacal liquor is simply concentrated ammonia.

<u>It has the following uses;</u>

Used as a refrigerant gas and in air-conditioning equipment.

Used to purify water supplies.

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6 0
3 years ago
What is the total number of electrons in a S2– ion?<br> (1) 10 (3) 16<br> (2) 14 (4) 18
jeka57 [31]
Sulfur normally has 16 electrons (see the periodic table), but the 2- indicates that the atom is gaining 2 electrons. because of that, the answer would be 18.
hope this helped!
4 0
4 years ago
Read 2 more answers
Suppose you want to prepare a buffer with a pH of 4.59 using formic acid. What ratio of [sodium formate]/[formic acid) do you ne
katrin [286]

Answer:

7.08

Explanation:

To solve this problem we'll use the <em>Henderson-Hasselbach equation</em>:

  • pH = pka + log\frac{[A^-]}{[HA]}

Where \frac{[A^-]}{[HA]} is the ratio of [sodium formate]/[formic acid] and pka is equal to -log(Ka), meaning that:

  • pka = -log (1.8x10⁻⁴) = 3.74

We<u> input the data</u>:

  • 4.59 = 3.74 + log\frac{[A^-]}{[HA]}

And<u> solve for </u>\frac{[A^-]}{[HA]}:

  • 0.85 = log\frac{[A^-]}{[HA]}
  • 10^{(0.85)}=\frac{[A^-]}{[HA]}
  • \frac{[A^-]}{[HA]} = 7.08
3 0
3 years ago
What is the pH at the half-equivalence point in the titration of a weak base with a strong acid? The pKb of the weak base is 7.9
ValentinkaMS [17]

Hey there!

Given the reaction:

B + H⁺   => HB⁺


At half-equivalence point :  [B] = [HB⁺]

=> [B] / [HB⁺] = 1

Henderson-Hasselbalch equation :


pH = pKa + log ( [B] ) / ( HB⁺)]

pH = 14 - pKb + log ( 1 )

pH = 14 -  7.95 + 0

pH = 6.05


Answer C


Hope that helps!



5 0
3 years ago
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