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3 years ago

10

Please help! 35 points for a valid answer!

2 answers:

Y_Kistochka [10]3 years ago

8 0

Answer:

The potential difference is caused by the ability of electrons to flow from one half cell to the other. Electrons are able to move between electrodes because the chemical reaction is a redox reaction. ... The cell potential (Ecell) is measured in voltage (V), which allows us to give a certain value to the cell potential.

Explanation:

Furkat [3]3 years ago

6 0

Answer:

Oxidation half reaction is written as follows when using using reduction potential chart

example when using copper it is written as follows

CU2+ +2e- --> c(s) +0.34v

oxidasation is the loos of electron hence copper oxidation potential is as follows

cu (s) --> CU2+ +2e -0.34v

Explanation:

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3 years ago

Read 2 more answers

Q#5 Balance and list the coefficients from reactants to products.

skad [1K]

A. $2Fe_2O_3(s) +3C(s)$ → $4Fe(s) + 3CO_2(g)$

B. $2Al(s) + 3FeO(s)$ → $Fe(s) + 3Al_2O_3(s)$

C. $2Al(s) +3H_2SO_4(aq)$ → $Al_2(SO_4)_3(aq) + 3H_2(g)$

What is a balanced chemical equation?

An equation that has an equal number of atoms of each element on both sides of the equation is called a balanced chemical equation.

A. $2Fe_2O_3(s) +3C(s)$ → $4Fe(s) + 3CO_2(g)$

B. $2Al(s) + 3FeO(s)$ → $Fe(s) + 3Al_2O_3(s)$

C. $2Al(s) +3H_2SO_4(aq)$ → $Al_2(SO_4)_3(aq) + 3H_2(g)$

Learn more about the balanced chemical equation here:

brainly.com/question/15052184

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8 0

2 years ago

Read 2 more answers

If 2 CH3OH + 3 O2 -> 2CO2 + 4 H2O was carried out in the laboratory and 219 g of water was produced, what would the percent y

ANEK [815]

Answer:

Percent yield = 84.5 %

Explanation:

Given data:

Mass of methanol = 229 g

Actual yield of water = 219 g

Percent yield of water = ?

Solution:

Chemical equation:

2CH₃OH + 3O₂ → 2CO₂ + 4H₂O

Number of moles of methanol:

Number of moles = mass/ molar mass

Number of moles = 229 g/ 32 g/mol

Number of moles = 7.2 mol

Now we will compare the moles of water with methanol.

CH₃OH : H₂O

2 : 4

7.2 : 4/2×7.2 = 14.4 mol

Mass of water:

Mass = number of moles × molae mass

Mass = 14.4 mol × 18 g/mol

Mass = 259.2 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 219 g / 259.2 g × 100

Percent yield = 84.5 %

7 0

3 years ago