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2 years ago

What is the solution to the equation 3x-5=2x+8+x?

1 answer:

6 0

So when solving this you are going to have to solve the equation.
Okay so first thing we need to do is simplify both sides of your equation so:
3x−5=2x+8+x
Simplifying process:
3x+−5=2x+8+x
Combine Like Terms ⇒ 3x−5=(2x+x)+(8)
3x−5=3x+8
3x−5=3x+8
Second thing we are now going to do is subtract 3x from both sides so:
3x−5−3x=3x+8−3x
−5=8
Final step is to add 5 to both sides:
−5+5=8+5
0=13
The answer to your question is "There are no solutions"

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Given f(x) = 4(x - 8), determine the value of f(10).

Ilya [14]

Answer:

f(10) = 8

Step-by-step explanation:

f(x) = 4(x - 8)

Let x = 10

f(10) = 4 ( 10-8)

= 4 ( 2)

= 8

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2 years ago

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2 years ago

I need help asap plz!!!

svet-max [94.6K]

Answer:

AC ≈ 10.3

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan48° = $\frac{opposite}{adjacent}$ = $\frac{AC}{AB}$ = $\frac{AC}{9.3}$ ( multiply both sides by 9.3 )

9.3 × tan48° = AC , then

AC ≈ 10.3 ( to 3 sf )

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2 years ago

Which answer is equivalent to ??? Help please

grigory [225]

Answer:

$\large\boxed{\dfrac{36}{25}}$

Step-by-step explanation:

$\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{5^{-2}\cdot9}{2^4\cdot4^{-3}}=(5^{-2}\cdot9):(2^4\cdot4^{-3})=\left(\dfrac{1}{5^2}\cdot9\right):\left(2^4\cdot(2^2)^{-3}\right)\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\left(\dfrac{1}{25}\cdot9\right):(2^4\cdot2^{-6})\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{9}{25}:2^{4+(-6)}=\dfrac{9}{25}:2^{-2}=\dfrac{9}{25}:\dfrac{1}{2^2}=\dfrac{9}{25}:\dfrac{1}{4}=\dfrac{9}{25}\cdot\dfrac{4}{1}=\dfrac{36}{25}$

7 0

3 years ago

A come and a pyramid has equal heights and volumes.if the base area of the pyramid is 154cm2.find the radius of the cone.

Dmitry_Shevchenko [17]

Answer:

Radius = 8.575 cm

Step-by-step explanation:

Formula for volume of a pyramid is;

V_p = ½Ah

Where A is area of base and h is height

Also, formula for volume of cone is given as;

V_c = ⅓πr²h

Now, we are told that V_p = V_c and that h is the same for both shapes.

Thus ;

½Ah = ⅓πr²h

h will cancel out to give;

½A = ⅓πr²

Cross multiply to give;

3A/2π = r²

Base area of pyramid is given as 154 cm². Thus;

(3 × 154)/2π = r²

r = √((3 × 154)/2π

r = 8.575 cm

4 0

2 years ago