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DedPeter [7]
3 years ago
12

What is the solution to the equation 3x-5=2x+8+x?

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0
So when solving this you are going to have to solve the equation.
Okay so first thing we need to do is simplify both sides of your equation so:
3x−5=<span>2x+8+x
</span>Simplifying process:
<span><span><span>3x</span>+</span>−5</span>=<span><span><span>2x</span>+8</span>+<span>x
</span></span><span>Combine Like Terms </span>⇒ 3x−5=<span>(2x+x)+(8)
</span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span>Second thing we are now going to do is s<span>ubtract 3x from both sides<span> so:
</span></span><span><span><span>3x</span>−5</span>−<span>3x</span></span>=<span><span><span>3x</span>+8</span>−<span>3<span>x
</span></span></span><span>−5</span>=<span>8
</span>Final step is to add 5 to both sides:
−5+5=<span>8+5
</span>0=<span>13
</span>The answer to your question is "<span>There are no solutions"</span>
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Bad gums may mean a bad heart. Researchers discovered that 79% of people who have suffered a heart attack had periodontal diseas
zysi [14]

Answer:

(A) 0.297

(B) 0.595

Step-by-step explanation:

Let,

H = a person who suffered from a heart attack

G = a person has the periodontal disease.

Given:

P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.15)+(0.33\times(1-0.15))\\=0.399

(A)

The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.15}{0.399} \\=0.29699\\\approx0.297

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.

(B)

Now if the probability of a person having a heart attack is, P (H) = 0.38.

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.38)+(0.33\times(1-0.38))\\=0.5048

Compute the probability of a person having a heart attack given that he or she has the disease:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.38}{0.5048}\\ =0.59469\\\approx0.595

The probability of a person having a heart attack given that he or she has the disease is 0.595.

4 0
3 years ago
Help on Number 8? I know Y=5 and the slope is undefined and x=2 but I don’t know what to do now.
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We know that 2 can fit into 5 twice, which means 2*2 is 4.

We now have 5 = 4 + b.

If 5 is b more than 4, then this means that 4 is b less than 5. Subtract 4 from both sides, and you will have b = 1.

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Answer with Step-by-step explanation:

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In this sequence,

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