Answer:
a) The ball goes one-third times higher on X
b) The ball goes three times higher on X.
Explanation:
a)
- As the initial velocity is the same than on Earth, but the free-fall acceleration is three times larger, this means that the only net force acting on the ball (gravity) will be three times larger, so it is clear that the ball will reach to a lower height, as it will slowed down more quickly.
- Kinematically, as we know that the speed becomes zero when the ball reaches to the maximum height, we can use the following kinematic equation:

since vf = 0, solving for Δh, we have:

if v₀ₓ = v₀E, and gₓ = 3*gE, replacing in (1), we get:
Δhₓ = 1/3 * ΔhE
which confirms our intuitive reasoning.
b)
- Now, if the initial velocity is three times larger than the one on Earth, even the acceleration due to gravity is three times larger, we conclude that the ball will go higher than on Earth.
- We can use the same kinematic equation as in (1) replacing Vox by 3*VoE, as follows:

Replacing the right side of (1) in (2), we get:
Δhx = 3* ΔhE
which confirms our intuitive reasoning also.
I haven't worked on Part-A, and I don't happen to know the magnitude of the gravitational force that the Sun exerts on the Earth.
But whatever it is, it's exactly, precisely, identical, the same, and equal to the magnitude of the gravitational force that the Earth exerts on the Sun.
I think that's the THIRD choice here, but I'm not sure of that either.
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Answer:
0.5 m
Explanation:
Two charges each of magnitude q
Let the third charge is Q is placed at a distance x from the origin so that the charge is in equilibrium.
The force on Q due to q at origin is balanced by the charge on Q due to the charge q placed at x = 1 m.
So,

1 - x = x
1 = 2x
x = 0.5 m
Thus, the third charge is placed at x = 0.5 m .
A longitudinal wave is also known as an oscillating wave. These waves affect the medium they are traveling through by disrupting what is either directly in front of behind them as they move.