<u>Statement</u><u>:</u>
A force is required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.
<u>To </u><u>find </u><u>out</u><u>:</u>
The force required to accelerate the ball.
<u>Solution</u><u>:</u>
- Mass of the ball (m) = 600 g = 0.6 Kg
- Initial velocity (u) = 0 m/s [it was at rest]
- Final velocity (v) = 14 m/s
- Time (t) = 0.1 s
- Let the acceleration be a.
- We know the equation of motion,
- v = u + at
- Therefore, putting the values in the above formula, we get
- 14 m/s = 0 m/s + a × 0.1 s
- or, 14 m/s ÷ 0.1 s = a
- or, a = 140 m/s²
- Let the force be F.
- We know, the formula : F = ma
- Putting the values in the above formula, we get
- F = 0.6 Kg × 140 m/s²
- or, F = 84 N
<u>Answer</u><u>:</u>
The force required to accelerate the ball is 84 N and this force acts along the direction of motion.
Hope you could understand.
If you have any query, feel free to ask.
Answer:
We could get the time taken by the ball to return back to earth, using the formula:
s = u t + ½ a t², where
s = displacement of the body moving with initial velocity u, acceleration 'a' in time t.
In the present case s=0 (as the ball returns back to starting time)
u= 30 m/s; a = -10 m/s² ( negative sign as a is in opposite direction to u); t=?
0 = 30 t - ½ ×10 ×t²; ==> 5 t = 30, t= 6 second.
So ball will return back after 6 second after being thrown up.
Explanation:
I looked it up
Hope this helps
Answer:
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Answer:
v= - 27 m/s
Explanation:
Given that
s= t³- 9 t²-27 ( Correct from sources)
As we know that velocity given as
v=3 t ² - 18 t ------------1
As we know that acceleration given as
v=3 t ² - 18 t
a=6 t -18
Given that acceleration is zero (a= 0 )
0 = 6 t - 18
t= 3 sec
Now by putting the values in the equation 1
v=3 t ² - 18 t m/s
v=3 x 3 ² - 18 x 3 m/s
v= 27 - 54 m/s
v= - 27 m/s
