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Nimfa-mama [501]
3 years ago
12

Planet X has three times the free-fall acceleration of Earth.

Physics
1 answer:
serious [3.7K]3 years ago
7 0

Answer:

a) The ball goes one-third times higher on X

b) The ball goes three times higher on X.

Explanation:

a)

  • As the initial velocity is the same than on Earth, but the free-fall acceleration is three times larger, this means that the only net force acting on the ball (gravity) will be three times larger, so it is clear that the ball will reach to a lower height, as it will slowed down more quickly.
  • Kinematically, as we know that the speed becomes zero when the ball reaches to the maximum height, we can use the following kinematic equation:

        v_{f} ^{2} - v_{o}^{2}  = 2* \Delta h* g

       since vf = 0, solving for Δh, we have:

       \Delta h = h_{max} =\frac{v_{o} ^{2}}{2*g} (1)

       if v₀ₓ = v₀E, and gₓ = 3*gE, replacing in (1), we get:

     Δhₓ = 1/3 * ΔhE

      which confirms our intuitive reasoning.

b)    

  • Now, if the initial velocity is three times larger than the one on Earth, even the acceleration due to gravity is three times larger, we conclude that the ball will go higher than on Earth.
  • We can use the same kinematic equation as in (1) replacing Vox by 3*VoE, as follows:

       \Delta h = h_{max} =\frac{(3*v_{o}) ^{2}}{2*3*g} (2)

      Replacing the right side of (1) in (2), we get:

      Δhx = 3* ΔhE

      which confirms our intuitive reasoning also.

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zubka84 [21]

Answer : Option C) Detective Smiley scanned the dim hallway. He pulled his pistol from its holster.

Explanation : Amongst the given other choices there seems to be no relationship between two consecutive sentences. The only sentence which seemed to have a connection between previous and later sentence was option C. Where it is clearly stated that the detective named as Smiley was walking through the hallway which was dimly lit. The second sentence has a co-relation to the previous one as it extends the sentence. Detective smiley then pulled out his pistol from his holster after walking through the hallway.

This confirms that the correct answer for this question is Option C.

8 0
3 years ago
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A typical incandescent light bulb consumes 75 W of power and has a mass of 30 g. You want to save electrical energy by dropping
nadya68 [22]

Answer:

The height will be 917431.2 m.

Explanation:

Power of bulb = 75 W

Time kept on 1 hr = 60 x 60 = 3600 sec

Energy of bulb = power x time

E = 75 x 3600 = 270000 J

From conservation of energy, kinetic energy of the bulb is equal to the potential energy of the bulb due to its height of fall.

Potential energy = m x g x h

Where g = acceleration due to gravity 9.81 m/s2

m = mass = 30 g = 0.03 kg

PE = 0.03 x 9.81 x h = 0.2943h

Equating withe the energy of bulb (still obeying energy conservation)

270000 = 0.2943h

h = 270000/0.2943 = 917431.2 m

8 0
4 years ago
A 7.45 nC charge is located 1.66 m from a 4.22 nC point charge. (a) Find the magnitude of the electrostatic force that one charg
BaLLatris [955]

Answer:

a.F=1.03\times 10^{-7}N

b.Repulsive

Explanation:

We are given that

q_1=7.45nC=7.45\times 10^{-9}C

1nC=10^{-9}C

q_2=4.22nC=4.22\times 10^{-9}C

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We know that

Electrostatic force =F=k\frac{q_1q_2}{r^2}

r=Distance between q_1\;and\;q_2

k=Constant=9\times 10^9Nm^2C^{-2}

Using the formula

a.The magnitude of the electrostatic force=F=\frac{9\times 10^9\times 7.45\times 10^{-9}\times 4.22\times 10^{-9}}{(1.66)^2}

The magnitude of the electrostatic force=F=1.03\times 10^{-7}N

b.Both charge are positive .We know that when like charges repel each other and unlike charges attract to each other.

Therefore, the force between given charges is repulsive.

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Answer:

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