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Nimfa-mama [501]
3 years ago
12

Planet X has three times the free-fall acceleration of Earth.

Physics
1 answer:
serious [3.7K]3 years ago
7 0

Answer:

a) The ball goes one-third times higher on X

b) The ball goes three times higher on X.

Explanation:

a)

  • As the initial velocity is the same than on Earth, but the free-fall acceleration is three times larger, this means that the only net force acting on the ball (gravity) will be three times larger, so it is clear that the ball will reach to a lower height, as it will slowed down more quickly.
  • Kinematically, as we know that the speed becomes zero when the ball reaches to the maximum height, we can use the following kinematic equation:

        v_{f} ^{2} - v_{o}^{2}  = 2* \Delta h* g

       since vf = 0, solving for Δh, we have:

       \Delta h = h_{max} =\frac{v_{o} ^{2}}{2*g} (1)

       if v₀ₓ = v₀E, and gₓ = 3*gE, replacing in (1), we get:

     Δhₓ = 1/3 * ΔhE

      which confirms our intuitive reasoning.

b)    

  • Now, if the initial velocity is three times larger than the one on Earth, even the acceleration due to gravity is three times larger, we conclude that the ball will go higher than on Earth.
  • We can use the same kinematic equation as in (1) replacing Vox by 3*VoE, as follows:

       \Delta h = h_{max} =\frac{(3*v_{o}) ^{2}}{2*3*g} (2)

      Replacing the right side of (1) in (2), we get:

      Δhx = 3* ΔhE

      which confirms our intuitive reasoning also.

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Answer:

distance and length are the same quantity

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Temperature flows from __ to __ temperatures
timama [110]

Answer:hot to cold

Explanation:

Temperature flow from hot to cold temperatures

8 0
3 years ago
In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t
OverLord2011 [107]

Answer:

a) h = 13,205.4 m

b)  r_f = 2.12 106 m

c)        e% = 0.68%

Explanation:

a) This is an exercise we are asked to use energy conservation,

Starting point. On the surface of Mimas

        Em₀ = K = ½ m v²

Final point. Where the ball stops

       Em_{f} = U = m g h

        Em₀ = Em_{f}

        ½ m v² = m g h

         h = ½ v² / g

let's calculate

         h = ½ 41² / 0.0636

         h = 13,205.4 m

b) For this part we are asked to use the law of universal gravitation, write the energy

starting point. Satellite surface

           Em₀ = K + U = ½ m v² - GmM / r_o

final point. Where the ball stops

            Em_{f}= U = - G mM / r_f

          Em₀ = Em_{f}

          ½ m v² - G m M / r_o = - G mM / r_f

In this case all distances are measured from the center of the satellite

         1 / rf = 1 / GM (-½ v² + G M / r_o)

     

let's calculate

         1 / rf = 1 / (6.67 10⁻¹¹ 3.75 10¹⁹) (- ½ 41 2 + 6.67 10⁻¹¹ 3.75 10¹⁹ / 1.98 105)

         1 / r_f = 3,998 10⁻¹¹(-840.5 + 12.63 10³)

          1 / r_f = 4,714 10⁻⁷

          r_f = 1 / 4,715 10⁻⁷

          r_f = 2.12 106 m

to measure this distance from the satellite surface

          r_f ’= r_f - r_o

          r_f ’= 2.12 106 - 1.98 105

         r_f ’= 1,922 106 m

c) the percentage difference is

          e% = 13 205.4 / 1,922 106 100

          e% = 0.68%

The estimate of part a is a little low

6 0
3 years ago
Find the work w1 done on the block by the force of magnitude f1 = 75.0 n as the block moves from xi = -1.00 cm to xf = 3.00 cm .
MissTica
<span>The work done is 3.0 Nm. We can us the equation Work = Force * Distance, where Force = 75.0 N, and distance is xf – xi = 3.00 cm - -1.00 cm = 4.00 cm. Convert centimeters to meters by moving the decimal place to the left by two places to get 0.04 m. Plug these values into the Work equation: Work = Force * Distance Work = 75.0 N * 0.04 m Work = 3.0 Nm</span>
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3 years ago
Is the momentum of a 0.1 kg Mass moving with a velocity of 5 miles per second West
dem82 [27]
<span>Momentum equals Mass x Velocity
Mass equals 0.1kg
Velocity equals 5m/s

So the momentum has to = 0.1 x 5 = 0.5kgm/s

I hope this helped
</span>
6 0
3 years ago
Read 2 more answers
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