1 mole = 6.022 * 10^23 formula units.
1.84*10^24 formula units CaCl₂ * (1 mole CaCl₂/6.022*10^23 formula units CaCl₂) = 3.06 moles of CaCl₂.
There are 3.06 moles of CaCl₂.
Answer:
0.75moles of H₄SiO₄
Explanation:
Given parameters:
Number of moles of H₂O = 1.5moles
Unknown:
Number of moles of H₄SiO₄ = ?
Solution:
To solve this problem, we need to write the reaction equation first;
SiO₂ + 2H₂O → H₄SiO₄
From the balanced reaction equation:
2 moles of water will produce 1 mole of H₄SiO₄
So 1.5 moles of water will produce 
= 0.75moles of H₄SiO₄
Answer:
The statement is considered to be true
Explanation:
The statement is true because when elements chemically combine, there are interactions between their valence electrons, causing the two elements to be bonded together to form what is known as a compound.
Compounds can only be formed from interactions between two or more elements. examples include:
Hydrogen + Oxygen = H2O (water)
Sodium + Chlorine = NaCl
Note that if atoms of the same element combine, what is formed is a molecule, not a compound. Some atoms usually do this to attain stability. examples include = O2 H2 and N2. They are oxygen molecule, hydrogen molecule, and nitrogen molecule respectively.
Compounds are only formed when different elements combine to attain electronic stability.
Answer:
The materials are opaque or crystalline from a client to the orientation and type of union between their atoms, forming two types of structures.
These two structures can be crystalline or amorphous.
In the case of being crystalline, these unions do not allow light to pass through the medium of the object or body of said compound, making it totally refract and giving the appearance of OPAQUE.
On the other hand, in those compounds that we call amorphous, the atoms are located in a different way that makes light pass through them, without absorbing or identifying any light beam, so they look transparent.
Explanation:
Example: A glass cup has an amorphous structure, while a porcelain or porcelain plate has a crystalline structure.
