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xeze [42]
2 years ago
8

How was the plum pudding model different from models that came after it

Chemistry
1 answer:
My name is Ann [436]2 years ago
8 0

Plum-pudding model is different from the model that came after it as the Plum pudding model did not encounter the concept of nucleus it simply says compares atom with a pudding in which electrons are spread around as rasins in a pudding while the model that came after that is Rutherford's model  explain that the atom that having nucleus that serves as a center of the atom.

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Pls help and show work!!!
kumpel [21]

Answer:

44.9g

Explanation:

You have to convert grams of CH4 to moles, use the mole-to-mole ratio of CH4 to water, and convert back to grams.

(20.0g CH4)(1 mol CH4/16.04g)(2 mol H2O/1 mol CH4)(18.01 g H2O/ 1 mol) = 44.9127 g

Hope this helps!

5 0
2 years ago
Read 2 more answers
That's how you can
kirza4 [7]
2)8/8-9_12-/78)022-/7/$
6 0
3 years ago
Which model of the atom is the most accurate
Zarrin [17]
Quantum Mechanical model (as per my knowledge)
7 0
3 years ago
Given 7.45 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
KengaRu [80]

The equation for the reaction is:

C₄H₈O₂ + C₂H₅OH = C₆H₁₂O₂ + H₂O

Now you see that the number of the moles of butanoic acid and etyl butyrate is equal in

the reaction. That means;

number of moles of C₄H₈O₂ = number of moles of C₆H₁₂O₂

mass of C₄H₈O₂/ Molar mass of C₄H₈O₂ = mass of C₆H₁₂O₂/ molar mass of C₆H₁₂O₂

mass of C₆H₁₂O₂ = molar mass of C₆H₁₂O₂ x mass of C₄H₈O₂/ Molar mass of C₄H₈O₂

Now, assuming <span>100% yield, the mass of ethyl butyrate produced is: </span>

<span>= 7.45/88.11 x 116.16</span>

<span>=9.82g</span>

<span>Thus, the theoretical yield of ethyl butyrate is 9.82g.</span>

3 0
2 years ago
Agustina was standing on the edge of a cliff of unknown height holding a bowling ball. She wanted to find the height of the clif
nlexa [21]

Answer:

433 m

Explanation:

Since the fall represents motion under gravity, we use the equation

s = ut - 1/2gt² where s = height of cliff or distance bowling ball falls through, u = initial velocity of bowling ball = 0 m/s(since it starts from rest), t = time = 9.4 s and g = acceleration due to gravity = -9.8 m/s².

So, substituting the values of the variables into the equation, we have

s = 0 m/s × 9.4 s - 1/2 × 9.8 m/s² × (9.4 s)²

s = 0 m - 1/2 × -9.8 m/s² × 88.36 s²

s = 1/2(865.928 m)

s = 432.964

s ≅ 433 m

5 0
2 years ago
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