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Nataly_w [17]
3 years ago
9

HELP WANTED, APPRECIATED, AND NEEDED ASAP

Mathematics
1 answer:
Anit [1.1K]3 years ago
4 0

Let's assume

x is number of hours worked

y is amount paid

Since, this is linear relationship

We can select any two points

(2,36.50) and (4,73)

so, we can also write as

x1=2 , y1 =36.50

x2=4 , y2=73

Firstly, we can find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{73-36.50}{4-2}

m=18.25

now, we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-36.50=18.25(x-2)

now, we can solve  for y

y=18.25x

or

y=18.3x..............Answer


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Answer:

  y = -3x +4

Step-by-step explanation:

The hint tells you the slope stays the same. Every point moves to 2 times its original distance from the origin. So, the new y-intercept will be (+2)(2) = +4. The dilated line is ...

  y = -3x +4

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3 years ago
Which of the following is an example of a measurement of acceleration?
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Acceleration = speed / time
acceleration = (m/s) / s
acceleration = m/s^2

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6 0
4 years ago
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ElenaW [278]
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3 0
3 years ago
Pru, Piper, and Phoebe share apples in the ratio 5:3:4. If Pru has 24 more apples than Piper, how many apples does Phoebe have?
Bezzdna [24]

Answer: Phoebe have 48 apples.

Explanation:

It is given that Pru, Piper, and Phoebe share apples in the ratio 5:3:4. If Pru has 24 more apples than Piper.

Let the total number of apples be x.

The sum of the ratios is,

Sum=5+3+4=12

Therefore the number of apples shared by Pru, Piper, Phoebe are \frac{5}{12}x, \frac{3}{12}x,\frac{4}{12}x respectively.

It is given that Pru has 24 more apples than Piper, so

\frac{5}{12}x-\frac{3}{12}x=24

\frac{5-3}{12}x=24

\frac{2}{12}x=24

\frac{1}{6}x=24

x=144

Since phoebe have \frac{4}{12}x appels,

\frac{4}{12}x=\frac{4}{12}\times 144=48

Therefore, Phoebe have 48 apples.

8 0
3 years ago
Read 2 more answers
What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0
Free_Kalibri [48]

Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, option B is true.

6 0
3 years ago
Read 2 more answers
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