A)
x=sales
4/100 x + 400≥460
b)
Solve the inequation:
4/100 x+400≥460
lest common multiple= 100
4x+40000≥46000
4x≥46000-40000
4x≥6000
x≥6000/4
x≥1500
answer: the minimun amount tha se will needs to sell is $1500.
The final answer/value of x is 6.
Answer:256 cows
Step-by-step explanation:
Let the total cow be a
3/4 of a
3/4 x a=3a/4
Remainder= a-3a/4=a/4
Remainder=a/4
3/4 Of The remainder
3/4 of a/4
3/4 x a/4=3a/16
New remainder will be
a/4-3a/16=a/16
New remainder is a/16
Therefore: a/16=16
Cross multiplying we get
a=16x16
a=256