In the diagram,angle;ABC=90 what is the radius of the circle

What is the value of (1/2)^3 + (1/3 x 2)?

Scilla [17]

Answer:

1/3x^2+1/8

Step-by-step explanation:

simplify the equation to 1/8+1/3x^2

7 0

3 years ago

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-7, -5), B(-

sergey [27]

The length of side CD is equal to 11 units.

Given coordinates of rectangle are A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5)

We are require to find the length of side CD.

Rectangle is a two dimensional figure whose two opposite sides are equal to each other. Distance between two coordinates is the equal to length of a side.

We know that the distance means how far two points are located.

Coordinates of A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5).

Distance= $\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} }$ where ( $x_{1} ,y_{2} )(x_{2} ,y_{2} )$ are the coordinates of two ends of a line.

CD= $\sqrt{(-5-6)^{2} +(-4+4)^{2} }$

= $\sqrt{11^{2}+0^{2} }$

= $\sqrt{121}$

=11 units.

Hence the length of side CD is 11 units.

Learn more about distance at brainly.com/question/17273444

#SPJ4

Question is wrong as it should be :

Coordinates of rectangle A(-7,-5), B(-7,6),C(-4,6) ,D(-4,-5) and find the length of CD.

8 0

2 years ago

The proportion of defective computers built by Byte Computer Corporation is 0.15. In an attempt to lower the defective rate, the

FinnZ [79.3K]

Answer:

a) Null hypothesis : H₀: the proportion of defective item of computer has been lowered. That is P < 0.15

Alternative hypothesis: H₁: The proportion of defective item of computer

has been higher. That is P> 0.15 (Right tailed test)

b) Test statistic $Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

c) Calculate the value of the test statistic = 0.991

d) The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57

e) Null hypothesis accepted at 0.01 level of significance

f) we accepted null hypothesis.

Hence the proportion of defective item of computer has been lowered.

Step-by-step explanation:

Step(i):-

Given the sample size 'n' = 42

Given random sample of 42 computers were tested revealing a total of 4 defective computers.

The defective computers 'x' = 4

The sample proportion of defective computers

$p = \frac{x}{n} = \frac{4}{42} = 0.095$

Given The Population proportion 'P' = 0.15

The level of significance ∝=0.01

Step(ii):-

a) Null hypothesis : H₀: the proportion of defective item of computer has been lowered. That is P < 0.15

Alternative hypothesis: H₁: The proportion of defective item of computer

has been higher. That is P> 0.15 (Right tailed test)

b)

Test statistic $Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

c)

$Z = \frac{0.095-0.15}{\sqrt{\frac{0.15(0.85)}{42} } }$

$z = \frac{-0.055}{\sqrt{0.00303} } = - 0.9991$

Calculate the value of the test statistic Z = - 0.9991

|Z| = |- 0.9991| = 0.991

Step(iii):-

d)

The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57

e) Calculate the value of the test statistic Z = 0.991 < 2.57 at 0.01 level of significance.

Conclusion:-

Hence the null hypothesis is accepted at 0.01 level of significance.

f)

The proportion of defective item of computer has been lowered.

6 0

3 years ago

I don’t feel like typing it out but can you guys help me on this one

lara31 [8.8K]

the answer is 4%

Hope this helps!

3 0

3 years ago

Read 2 more answers

URGENT DUE BY 3:30 FOR A HUGE GRADE WILL RATE GOOD:)

mariarad [96]

A = L x W

20 x 20 = 400.

400 x 8 = 3200

4 0

3 years ago