Question

A 55.0 L sample of gas at 235 K exerts a pressure of 225 KPa. If its volume is decreased to 42.0 L and the temperature rises to 315 K, what is its new pressure?

Answer 1

Answer:

Final pressure will be equal to 394.94 kPa

Explanation:

It is given volume $V_1=55L$

Temperature of the gas $T_1=235K$

Initial pressure exerted $P_1=225kPa$

Now volume is decreased to $V_2=42L$

And temperature is increases to $T_2=315K$

By using gas equation

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$\frac{225\times 55}{235}=\frac{P_2\times 42}{315}$

$P_2=394.94kPa$

So final pressure will be equal to 394.94 kPa