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2 years ago

Which element is reduced in the reaction below? A. Na B. CI C. Ba D. None

Chemistry

2 answers:

stellarik [79]2 years ago

5 0

Answer: The correct answer is Option D.

Explanation:

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow NaCl(aq.)+BaSO_4(s)$

The above chemical reaction is considered as double displacement reaction because here exchange of ions takes place.

In these type of reactions, oxidation state of the atoms remains the same.

On the reactant side:

Oxidation state of barium = +2

Oxidation state of chlorine = -1

Oxidation state of sodium = +1

On the product side:

Oxidation state of barium = +2

Oxidation state of chlorine = -1

Oxidation state of sodium = +1

Thus, the correct answer is Option D.

anastassius [24]2 years ago

3 0

The answer is D) None
You were correct!

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Answer:

The answer is given below.

Explanation:

We will consider the acid as HA and will set up an ICE table with the equilibrium dissociation of α.

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Initial concentration: 0.1 → 3.98 ^10-3 + 0

equilibrium concentration: 0.1(1-α) → 3.98 * 10-3 + 0.1α 0.1α

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-log(Ka) = 2.9

Ka = 1.26 * 10-3

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Since α<<1, we assume 1-α = 1

Solving the equation, we have: α = 0.094

Since this is the fraction of acid that has dissociated, we can say that % of base form = 100 * α= 9.4%

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