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3 years ago

Which element is reduced in the reaction below? A. Na B. CI C. Ba D. None

Chemistry

2 answers:

stellarik [79]3 years ago

5 0

Answer: The correct answer is Option D.

Explanation:

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow NaCl(aq.)+BaSO_4(s)$

The above chemical reaction is considered as double displacement reaction because here exchange of ions takes place.

In these type of reactions, oxidation state of the atoms remains the same.

On the reactant side:

Oxidation state of barium = +2

Oxidation state of chlorine = -1

Oxidation state of sodium = +1

On the product side:

Oxidation state of barium = +2

Oxidation state of chlorine = -1

Oxidation state of sodium = +1

Thus, the correct answer is Option D.

anastassius [24]3 years ago

3 0

The answer is D) None
You were correct!

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A. NH3
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3 years ago

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an irregularly shaped solid is dropped into a graduated cylinder filled with 45.00 mL of water. the water level with the object

posledela

The density of the object is 1.96 g/cm³.

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3 years ago

QUESTION 5

Elenna [48]

B. 3.77 L is the new volume occupied by the gas.

Explanation:

As per Avogadro's law, which states that if the pressure and temperature held constant, then an equal volume of the gases will occupy an equal number of molecules. It can be written as,

$$\frac{V1}{n1} = \frac{V2}{n2}\\$

Here, V1, volume of the helium gas = 2.9 L

V2, volume of the additional helium gas in the balloon = ?

n1, moles of helium gas = 0.150 mol

n2, number of moles of additional helium gas = 0.150 + 0.0450 = 0.195 mol

We have to rearrange the equation for V2 as,

V2 = $$\frac{V1n2}{n1}$

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V2 = $$\frac{2.9 L \times 0.195 mol}{0.150 mol}$

= 3.77 L

So the new volume of the balloon is 3.77 L.

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3 years ago

What is the frequency of light with an energy of 124 kJ/mol?

Charra [1.4K]

Answer: = 3.11 x 10^14 s^-1

Explanation:

Use the formula E = hv

This formula uses the assumption that the unit for energy is in Joules/photon.

124 kJ = 124000J

To get 124000J/mol into a unit of J/photons, we need to divide by the number of photons in a mole, which is 6.022 x 10^23.

And thus, we need

124000/6.022 x 10^23 = 2.06 x 10^-19J/photon

We can plug it in to E = hv by

2.06 x 10^-19J = (6.63 x 10^-34 J s)(v) Isolate v by

v = (2.06 x 10^-19J)/(6.63 x 10^-34 J s)

= 3.11 x 10^14 s^-1

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3 years ago

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Alexxandr [17]

Answer:

Ye,,it is true that Mars is bigger than mercury.

Explanation:

Actually,Mercury is the smallest planet in the solar system.

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