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Maurinko [17]
3 years ago
10

A flask filled with oxygen is heated from 5 degrees Celsius to 30 degrees Celsius. The starting pressure was 50 kPa, what is the

final pressure? (Be sure to convert from Celsius to Kelvin, add 273 to your Celsius temperature to get the temperature to kelvin. Ex. 0 degrees Celsius id equal to 273 kelvin)
Chemistry
1 answer:
rewona [7]3 years ago
6 0

54.5kPa

Explanation:

Given parameters:

T₂ = 30°C = 30+273 = 303K

T₁ =  5°C = 5+273 = 278K

P₁ = 50kPa

Unknown:

P₂ = ?

Solution:

We can solve this problem using the combined gas law simplification and assuming that volume is constant as seen from the container:

            \frac{P_{1} }{T_{1} } =  \frac{P_{2} }{T_{2} }

Making the unknown the subject of the formula:

            P₂ = \frac{P_{1} T_{2} }{T_{1} }

             P₂ = \frac{50 x 303}{278} = 54.5kPa

Learn more:

Ideal gas brainly.com/question/9321544

#learnwithBrainly

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Answer:

B. 1:2

Explanation:

Molar ratio depicts the relationship between the number of moles of two substances. The chemical equation in this question is as follows:

2H2 + O2 → 2H2O

This question is asking to identify the molar ratio of O2 to H2O in the equation. Since 1 mole of oxygen gas (O2) produces 2 moles of water (H2O). Hence, the O2 to H2O molar ratio is 1:2.

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A sample of gold (Au) has a mass of 45.39 g.
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<span>1. What is the molar mass of gold?
Molar mass is a unit that expresses the mass of a molecule per one mol. The molar mass can be obtained by adding the neutron with the proton of the atoms. Gold has atomic number 79 so the proton is 79. The number of the neutron is 118. Then the molar mass would be: 79 + 118 = </span>197 g/mol<span>


</span><span>2. Calculate the number of moles of gold (Au) in the sample. Show your work. 
</span>In this question, you are given the mass of the gold and asked for how many moles the sample has. To find the number of moles you just need to divide the weight by the molar mass.
For 45.39 grams of gold, the number of moles would be:
45.39 / (197g/mol)= 0.23 moles


3. Calculate the number of atoms of gold (Au) in the sample. Show your work.Moles is unit of a number of molecules but 1 mol doesn't represent 1 molecule. The number of atoms can be obtained by multiplying the number of moles with Avogadro number. The calculation would be:
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8 0
3 years ago
A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %
kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and y_{C-6} and y_{N_2} are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

Q=-40036+(-672.21)=-40708.21J

Finally we convert this result to kJ:

Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ

Learn more:

  • brainly.com/question/25475410
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