Answer:
A sample size of 6755 or higher would be appropriate.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error M is given by:
90% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
52% of Independents in the sample opposed the public option.
This means that 
If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?
Sample size of size n or higher when 
. So
A sample size of 6755 or higher would be appropriate.
Answer:
The answer is never true
Step-by-step explanation:
Can you please give me brainliest
Answer: 4 pounds of wooden blocks and 6 pounds of plastic bricks should be used.
Step-by-step explanation:
Let x = Quantity of wooden blocks.
y = Quantity of plastic bricks.
As per given , we ahve
5x+10y=80 (i)
x+y=10 (ii)
Multiply 5 on both sides of (ii), we get
5x+5y=50 (iii)
Eliminate (i) from (iii), we get
5y=30
⇒ y= 6
Put y=6 in (ii), we get
x+6=10
⇒ x= 10-6= 4
Hence, 4 pounds of wooden blocks and 6 pounds of plastic bricks should be used.
I don't understand your question.. Is this multiple choice or something else?
