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tresset_1 [31]
3 years ago
6

How would a fast-flowing river be most likely to move sand-sized particles of sediment?

Chemistry
1 answer:
Nitella [24]3 years ago
3 0
A fast-flowing river would most likely be to move the skaters glide around the rink b<span>y lifting it up and carrying it downstream. In a fast-flowing river, the pressure is strong, which makes it easier for sand-sized particles of sediments to be carried or transferred. Hope this answer helps.</span>
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How many moles are 3.20 x102 formula units of calcium iodide?
DedPeter [7]

The number of moles in 3.20 x 10² formula units of calcium iodide is 0.053 moles.

<h3>How to calculate number of moles?</h3>

The number of moles in the formula units of a substance is calculated by dividing the formula unit by Avogadro's number.

According to this question, 3.20 x 10² formula units are in calcium iodide. The number of moles is as follows:

no of moles = 3.20 x 10²² ÷ 6.02 × 10²³

no of moles = 0.53 × 10-¹

no of moles = 0.053 moles

Therefore, the number of moles in 3.20 x 10² formula units of calcium iodide is 0.053 moles.

Learn more about number of moles at: brainly.com/question/12513822

#SPJ6

3 0
2 years ago
Read 2 more answers
1. Which of the following is an SI base unit for time? (2 points)
oee [108]
Number one would be Decades
6 0
3 years ago
Determine which choice is an example of an endothermic process.
klemol [59]

Answer:

D. Baking bread

Explanation:

In this process, energy is absorbed and in an endothermic process energy is absorbed too.

6 0
3 years ago
A compound has a molar mass of 86.0 g/mol and an empirical formula of C3H7 what is the molecular formula
zmey [24]
The formula for the molecular formula is molar mass/ empirical formula

So, the empirical formula of C3H7 is equal to C*3 + H*7 which is equal to 12*3 +  7. Then use the molecular formula = 86 / (12*3+7) = 2

Therefore, the molecular formula is 2 times the empirical formula which is C6H14.
3 0
3 years ago
If 5g of H2 are reacted with excess CO, how many grams of CH3OH are produced, based on a yield of 86%?
Cerrena [4.2K]

Answer: 34.4 g

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of hydrogen}=\frac{5g}{2g/mol}=2.5moles

As CO is in excess, H_2 is the limiting reagent and thus it will limit the formation of products.

CO+2H_2\rightarrow CH_3OH

According to stoichiometry:

2 moles of hydrogen produce = 1 mole of CH_3OH

2.5 moles of hydrogen produce = \frac{1}{2}\times 2.5=1.25 moles of CH_3OH

Mass of CH_3OH=moles\times {\text {Molar mass}}=1.25\times 32=40g

But as % yield is 86%, mass of CH_3OH produded is \frac{86}{100}\times 40=34.4g

Thus 34.4 g of CH_3OH is produced.

6 0
3 years ago
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