Answer: 166.023×1023
Explanation:
Mass of 6.023×1023 atoms of oxygen = gram atomic mass of oxygen.
Mass of 6.023×1023 atoms of oxygen = 16g
∴ Mass of 1 atom of oxygen =166.023×1023
<u>Given:</u>
Surface area at the narrow end, A1 = 5.00 cm2
Force applied at the narrow end, F1 = 81.0 N
Surface area at the wide end, A2 = 725 cm2
<u>To determine:</u>
Force F2 applied at the wide end
<u>Explanation:</u>
Use the relation
F1/A1 = F2/A2
F2 = F1*A2/A1 = 81.0 N * 725 cm2/5.00 cm2 = 11,745 N
Ans: (b)
The force applied at the wide end = 11,745 N
Answer:
0.375 grams are needed to make 25 mL solution.
Explanation:
Mass of 
cuprous nitrate required to make 1 l of solution = 15 g.
1 L = 1000 mL
Mass of cuprous nitrate required to make 1000 mL of solution = 15 g
Mass of cuprous nitrate required to make 1 mL of solution:
Mass of cuprous nitrate required to make 25 mL of solution:
0.375 grams are needed to make 25 mL solution.
Answer:
a
Explanation:
because I said so and I think it's right
Answer:
Ca(OH)2 +CO2========CaCO3 +H2O
Explanation:
since the number of elements in the right is equal to that of the elements in the left side shows it is balanced
