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9966 [12]
4 years ago
5

Calculate the compound amount. Use the compound amount formula and a calculator. (Round your answer to two decimal places.) P =

$1100, r = 9% compounded semiannually, t = 14 years
Chemistry
1 answer:
Julli [10]4 years ago
5 0

Answer:

The compound amount is $303.03 .

Explanation:

Formula for compound interest:

A=P\times (1+\frac{R}{n})^{tn})

Principle amount  = $1100

Rate of the interest compounded semiannually :

= R = 9% = 0.09

Number of times interest compounded, n = \frac{12}{6}=2

(semi means two times in a year)

Time period = T = 14

A=\$1100\times (1+\frac{0.09}{2})^{2\times 14}=\$303.0310\approx \$303.03

The compound amount is $303.03 .

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Convert 1.25 atm to bar.
Tasya [4]

Answer: 1.27 bar

Explanation:

1 atm = 1.01325 bar

1.25 atm = Z (let Z be the unknown value)

To get the value of Z, cross multiply

Z x 1 atm = 1.25 atm x 1.01325 bar

1 atm•Z = 1.2665625 atm•bar

To get the value of Z, divide both sides by 1 atm

1 atm•Z/1 atm = 1.2665625 atm•bar/1atm

Z = 1.2665625 bar

(Round up Z to the nearest hundredth as 1.27 bar)

Thus, 1.25 atm when coverted gives 1.27 bar

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3 years ago
#1: Which of the following statements is true?
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I really hope this helps, and I'm sorry if it doesn't It would be great if you posted the answer choices too.

3 0
3 years ago
When 2.714 g of AX (s) dissolves in 127.4 g of water in a coffee-cup calorimeter the temperature rises from 23.3 °C to 37.1 °C.
MakcuM [25]

Answer : The enthalpy change for the solution is 166.34 kJ/mol

Explanation :

First we have to calculate the enthalpy change of the reaction.

Formula used :

\Delta H=mC\Delta T\\\\\Delta H=mC(T_2-T_1)

where,

\Delta H = change in enthalpy = ?

C = heat capacity of water = 4.18J/g.K

m = total mass of sample = 2.174 + 127.4 = 129.6 g

T_1 = initial temperature = 23^oC=273+23=296K

T_2 = final temperature = 37.1^oC=273+37.1=310.1K

Now put all the given values in the above expression, we get:

\Delta H=mC(T_2-T_1)

\Delta H=129.6g\times 4.18J/g.K\times (310.1-296)K=7638.36J

Now we have to calculate the moles of AX added to water.

\text{ Moles of }AX=\frac{\text{ Mass of }AX}{\text{ Molar mass of }AX}=\frac{2.714g}{59.1097g/mole}=0.04592moles

Now we have to calculate the enthalpy change for the solution.

As, 0.04592 moles releases heat = 7638.36 J

So, 1 moles releases heat = \frac{7638.36}{0.04592}=166340.59J=166.34kJ

Therefore, the enthalpy change for the solution is 166.34 kJ/mol

7 0
3 years ago
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