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erastovalidia [21]
3 years ago
10

A turtle swimming in a straight line toward shore has a speed of 0.50 m/s.  After 4.0 s, its speed is 0.80 m/s.  What is the tur

tle's average acceleration?
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0
<span>(0.80-0.5 m/s)/(4.0 s) = (0.075 m)/s^2</span>
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Kermit The Frog could eat 8 flies in 30 minutes. How long would it take Kermit to eat 20 flies? (write the answer in minutes ¬¬¬
Vedmedyk [2.9K]

Answer:

75 minutes

Step-by-step explanation:

5 0
3 years ago
The difference between 6 times a number and 10 is 32. Find the number. (I also need the equation)
IceJOKER [234]
The equation :

6x - 10 = 32

the number

x = 7
6 0
3 years ago
Read 2 more answers
3(c+5)=12. Distributive property
avanturin [10]

Answer:

c = -1

Step-by-step explanation:

3(c+5)=12

3 × c = 3c

3 × 5 = 15

3c + 15 = 12

<u>      - 15   -15</u>

   3c = -3

c = -3 ÷ 3 = -1

Check:

3(-1+5)=12

-3 + 15 = 12

6 0
3 years ago
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There are exactly 2.54 centimeters in 1 inch. When using this conversion factor, how many significant figures are you limited t
IgorC [24]

Significant figures tells us that about how may digits we can count on to be precise given the uncertainty in our calculations or data measurements.

Since, one inch  = 2.54 cm.

This is equivalent as saying that 1.0000000.. inch = 2.540000... cm.

Since the inch to cm conversion doesn't add any uncertainty, so we are free to keep any and all the significant figures.

Since, being an exact number, it has an unlimited number of significant figures and thus when we convert inch to cm we multiply two exact quantities together. Therefore, it will have infinite number of significant figures.

5 0
3 years ago
A sample of radium has a weight of 1.5 mg and a half-life of approximately 6 years.
pogonyaev

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

5 0
3 years ago
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