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AlekseyPX
4 years ago
10

You know that an unlabeled water bottle contains at least some water. You measure the freezing point of the unknown substance an

d find that it freezes at a temperature lower than 0 degrees Celsius at 1 atmosphere pressure. Which of the following can you conclude?
The substance is pure water.

The substance will have a boiling point that is less than 100 degrees Celsius.

The substance will have a vapor pressure that is greater than that of pure water.

The substance is an aqueous solution.
Chemistry
2 answers:
jeyben [28]4 years ago
6 0
You know that an unlabeled water bottle contains at least some water. You measure the freezing point of the unknown substance and find that it freezes at a temperature lower than 0 degrees Celsius at 1 atmosphere pressure, <span>The substance will have a boiling point that is less than 100 degrees Celsius.</span>
Tcecarenko [31]4 years ago
4 0

The substance is an aqueous solution

An aqueous solution that contains non-volatile solute will have a lower freezing point, higher boiling point, and lower vapor pressure compared to pure water

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Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so
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Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For NaOH :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{90.0\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 2.2502\ mol

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M

<u>Final concentration of NaOH = 0.75 M</u>

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