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3 years ago

The atomic size of zirconium is smaller than

Chemistry

1 answer:

d1i1m1o1n [39]3 years ago

5 0

Answer:

Explanation:

because hahamaskdjdjskskskskkssksksks

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Balance the equation NH4OH + H3PO4 What Are the products of NH4OH + H3PO4

Troyanec [42]

Answer:

3NH₄OH + H₃PO₄ → (NH₄)₃PO₄ + 3H₂O

Products are water and ammonium phosphate

Explanation:

This is a neutralization between a weak base and a weak acid where the products are water and the correspondent salt.

Base: NH₄OH → NH₄⁺ + OH⁻

Acid : H₃PO₄ → 3H⁺ + PO₄⁻³

H⁺ bonds to OH⁻ to make H₂O → As we have 3 protons, we can make 3 moles of water, so there are needed 3 OH⁻.

Phosphate has -3 as oxidation state, then it needs 3 ammonium to form the salt.

The balanced equation is:

3NH₄OH + H₃PO₄ → (NH₄)₃PO₄ + 3H₂O

6 0

4 years ago

Picture a neutral S atom. This neutral atom will have

asambeis [7]

Answer:

has 6 valence electrons as its in group 6

the atom will gain electrons

the charge will be 2- as it will gain 2 electrons to be a full configuration

8 0

3 years ago

The number of moles of H+ ions in a liter of distilled (pure) water is:

alukav5142 [94]

At room temperature, number of moles of distilled water is 1 x10^-7. Hope it cleared your doubt.

5 0

3 years ago

Read 2 more answers

Gaseous compound Q contains only xenon and oxygen. When 0.100 gg of Q is placed in a 50.0 mLmL steel vessel at 0 ∘C∘C, the press

asambeis [7]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.229 atm. What is the likely formula of the compound?

A. XeO

B. $XeO_4$

C. $Xe_2O_2$

D. $Xe_2O_3$

E. $Xe_3O_2$

Answer: The chemical formula of the compound is $XeO_4$

Explanation:

To calculate the molecular mass of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{w}{M}RT$

where,

P = Pressure of the gas = 0.229 atm

V = Volume of the gas = 50.0 mL = 0.050 L (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = Temperature of the gas = $0^oC=273K$

Putting value in above equation, we get:

$0.229\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.229\times 0.050}=195.4g/mol\approx 195g/mol$

The compound having mass as 195 g/mol is $XeO_4$

Hence, the chemical formula of the compound is $XeO_4$

5 0

3 years ago

What is the balanced chemical equation for the reaction of aqueous sodium hydroxide and sulfuric acid?

Andrews [41]

Answer:

H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O).

Explanation:

6 0

3 years ago